anonymous
  • anonymous
Evaluate the integral. The integral will be entered below. The title of this section is Intergration of Rational Fractions by Partial Fractions
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[\int\limits_{}^{}\frac{ x^2+2x-1 }{ x^3-x }dx\]
anonymous
  • anonymous
I can simplify it down to \[\int\limits_{}^{}\frac{ A }{ x }+\frac{ B }{ x-1 }+\frac{ C }{ x+1 }\] but get lost when solving for A, B and C
anonymous
  • anonymous
oops forgot a dx there

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
do u want answer or explanation
anonymous
  • anonymous
explanation my math teacher was very confusing when going over this section (thick accent)
anonymous
  • anonymous
I probably screwed up because its three terms now instead of two
anonymous
  • anonymous
I had \[x^2+2x-1=Ax+B(x-1)+C(x+1)\] which is obviously wrong
anonymous
  • anonymous
i m lost
anonymous
  • anonymous
yea this method is past l'Hopital's rule which I think you said you did not know earlier so it might be a little higher than your current level of math course
anonymous
  • anonymous
first factor the function
anonymous
  • anonymous
which I did getting x(x-1)(x+1) on the bottom
anonymous
  • anonymous
yes that is true
zepdrix
  • zepdrix
\[\large \frac{x^2+2x-1}{x(x-1)(x+1)} \qquad =\qquad \frac{A}{x}+\frac{B}{x-1}+\frac{C}{x+1}\]You should set it up like this. It looks like you're on the right track. You just didn't multiply through correctly.
zepdrix
  • zepdrix
Multiply both sides by the denominator on the left. :O
anonymous
  • anonymous
O GOD top ten list of signs I need to go to bed
anonymous
  • anonymous
so the correct answer is \[x^2+2x-1=A(x+1)(x-1)+Bx(x+1)+Cx(x-1)\]\[=(A+B+C)X^2+(B-C)X-A\]\[A=1, B=1, C=-1\]
zepdrix
  • zepdrix
Yah that looks right :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.