aussy123
Given the point (3, 4), which of the following shows that sinxcscx = 1?
(3/4)(4/3) = 1
(3/5)(5/3) = 1
(4/5)(5/4) = 1



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hartnn
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Given the point (3, 4), can you find sin x=...?

aussy123
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I think ......Ill show a graph

aussy123
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dw:1363005355574:dw

hartnn
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wait

Mertsj
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dw:1363005499577:dw

hartnn
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(3,4) means xcoordinate = 3
y coordinate =4, so it'll be
dw:1363005449516:dw
can you find the hypotenuse = b= ...?
using pythagoras theorem ?

aussy123
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yes

hartnn
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then can you find sin x = opposite side/hypotenuse =... ?

hartnn
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dw:1363005619712:dw

aussy123
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a^2+b^2=c^2
3^2+b^2=4^2
9+b^2=16
b^2=7
\[\sqrt{7}\]

Mertsj
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\[a^2+b^2=c^2\]

Mertsj
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\[3^2+4^2=c^2\]

hartnn
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you've taken incorrect sides...
a= 3, b=4
find c=hypotenuse =..?

Mertsj
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\[9+16=c^2\]

Mertsj
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\[25=c^2\]

Mertsj
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\[5=c\]

aussy123
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oh Im sorry
9+16=25
c^2=25
5=c

hartnn
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thats correct, now sin x = opposite side / hypotenuse =...?

aussy123
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oh it 4/5

hartnn
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yup, and csc x = hypotenuse/opposite side =...?

aussy123
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5/4

hartnn
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thats it,
so (4/5)(5/4)=1

aussy123
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Yayy Thanks, this was really helpful, Ill try this on the rest of my problems!

hartnn
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welcome ^_^