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aussy123

  • one year ago

Given the point (3, 4), which of the following shows that sinxcscx = 1? (3/4)(4/3) = 1 (3/5)(5/3) = 1 (4/5)(5/4) = 1

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  1. hartnn
    • one year ago
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    Given the point (3, 4), can you find sin x=...?

  2. aussy123
    • one year ago
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    I think ......Ill show a graph

  3. aussy123
    • one year ago
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    |dw:1363005355574:dw|

  4. hartnn
    • one year ago
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    wait

  5. Mertsj
    • one year ago
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    |dw:1363005499577:dw|

  6. hartnn
    • one year ago
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    (3,4) means x-co-ordinate = 3 y co-ordinate =4, so it'll be |dw:1363005449516:dw| can you find the hypotenuse = b= ...? using pythagoras theorem ?

  7. aussy123
    • one year ago
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    yes

  8. hartnn
    • one year ago
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    then can you find sin x = opposite side/hypotenuse =... ?

  9. hartnn
    • one year ago
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    |dw:1363005619712:dw|

  10. aussy123
    • one year ago
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    a^2+b^2=c^2 3^2+b^2=4^2 9+b^2=16 b^2=7 \[\sqrt{7}\]

  11. Mertsj
    • one year ago
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    \[a^2+b^2=c^2\]

  12. Mertsj
    • one year ago
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    \[3^2+4^2=c^2\]

  13. hartnn
    • one year ago
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    you've taken incorrect sides... a= 3, b=4 find c=hypotenuse =..?

  14. Mertsj
    • one year ago
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    \[9+16=c^2\]

  15. Mertsj
    • one year ago
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    \[25=c^2\]

  16. Mertsj
    • one year ago
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    \[5=c\]

  17. aussy123
    • one year ago
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    oh Im sorry 9+16=25 c^2=25 5=c

  18. hartnn
    • one year ago
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    thats correct, now sin x = opposite side / hypotenuse =...?

  19. aussy123
    • one year ago
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    oh it 4/5

  20. hartnn
    • one year ago
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    yup, and csc x = hypotenuse/opposite side =...?

  21. aussy123
    • one year ago
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    5/4

  22. hartnn
    • one year ago
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    thats it, so (4/5)(5/4)=1

  23. aussy123
    • one year ago
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    Yayy Thanks, this was really helpful, Ill try this on the rest of my problems!

  24. hartnn
    • one year ago
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    welcome ^_^

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