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lvasquev462

  • 2 years ago

Algebra 1 help

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  1. lvasquev462
    • 2 years ago
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    |dw:1363018027305:dw|

  2. lvasquev462
    • 2 years ago
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    ists 2x squared and 5x squared

  3. phi
    • 2 years ago
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    you can use ^ to show exponents -14+2x^2 -3x + 5x^2 + 6-6x better use the equation editor \[ -14+2x^2 -3x + 5x^2 + 6-6x \]

  4. phi
    • 2 years ago
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    when adding you can change the order so you could write it like this \[ 5x^2 + 2x^2 -3x-6x-14+6 \]

  5. phi
    • 2 years ago
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    it should be clear what -14+6 is for the x^2 terms: if you have 5 x^2 terms and add 2 more x^2 terms, how many x^2 terms do you have ?

  6. lvasquev462
    • 2 years ago
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    -8

  7. lvasquev462
    • 2 years ago
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    and \[x ^{2}\]

  8. phi
    • 2 years ago
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    if you have 5 x^2 terms and add 2 more x^2 terms, how many x^2 terms do you have ?

  9. phi
    • 2 years ago
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    if you think of x^2 as a "thing" and you have 5 of them and add 2 more, how many do you have ?

  10. lvasquev462
    • 2 years ago
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    7 x \[7x ^{2}\]

  11. phi
    • 2 years ago
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    yes 7 x^2 so far you have \[ 7x^2 -3x-6x-8 \] now how many of the x's

  12. lvasquev462
    • 2 years ago
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    2 x's because 3x and 6x right

  13. phi
    • 2 years ago
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    it is -3x -6x we could "factor out" the x to get (-3-6) x now what is -3-6 ?

  14. lvasquev462
    • 2 years ago
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    3

  15. lvasquev462
    • 2 years ago
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    is the 6 a negative too

  16. lvasquev462
    • 2 years ago
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    if the six is negative it be -9 right

  17. phi
    • 2 years ago
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    yes -3-6 is -9 so the answer is -9x the whole answer is \[ 7x^2 -9x-8 \] if negative numbers are unclear, see http://www.khanacademy.org/math/arithmetic/absolute-value/adding_subtracting_negatives/v/negative-numbers-introduction

  18. lvasquev462
    • 2 years ago
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    Thank you

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