Here's the question you clicked on:
lvasquev462
Algebra 1 help
|dw:1363018027305:dw|
ists 2x squared and 5x squared
you can use ^ to show exponents -14+2x^2 -3x + 5x^2 + 6-6x better use the equation editor \[ -14+2x^2 -3x + 5x^2 + 6-6x \]
when adding you can change the order so you could write it like this \[ 5x^2 + 2x^2 -3x-6x-14+6 \]
it should be clear what -14+6 is for the x^2 terms: if you have 5 x^2 terms and add 2 more x^2 terms, how many x^2 terms do you have ?
if you have 5 x^2 terms and add 2 more x^2 terms, how many x^2 terms do you have ?
if you think of x^2 as a "thing" and you have 5 of them and add 2 more, how many do you have ?
yes 7 x^2 so far you have \[ 7x^2 -3x-6x-8 \] now how many of the x's
2 x's because 3x and 6x right
it is -3x -6x we could "factor out" the x to get (-3-6) x now what is -3-6 ?
is the 6 a negative too
if the six is negative it be -9 right
yes -3-6 is -9 so the answer is -9x the whole answer is \[ 7x^2 -9x-8 \] if negative numbers are unclear, see http://www.khanacademy.org/math/arithmetic/absolute-value/adding_subtracting_negatives/v/negative-numbers-introduction