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anonymous
 3 years ago
Algebra 1 help
anonymous
 3 years ago
Algebra 1 help

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1363018027305:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ists 2x squared and 5x squared

phi
 3 years ago
Best ResponseYou've already chosen the best response.1you can use ^ to show exponents 14+2x^2 3x + 5x^2 + 66x better use the equation editor \[ 14+2x^2 3x + 5x^2 + 66x \]

phi
 3 years ago
Best ResponseYou've already chosen the best response.1when adding you can change the order so you could write it like this \[ 5x^2 + 2x^2 3x6x14+6 \]

phi
 3 years ago
Best ResponseYou've already chosen the best response.1it should be clear what 14+6 is for the x^2 terms: if you have 5 x^2 terms and add 2 more x^2 terms, how many x^2 terms do you have ?

phi
 3 years ago
Best ResponseYou've already chosen the best response.1if you have 5 x^2 terms and add 2 more x^2 terms, how many x^2 terms do you have ?

phi
 3 years ago
Best ResponseYou've already chosen the best response.1if you think of x^2 as a "thing" and you have 5 of them and add 2 more, how many do you have ?

phi
 3 years ago
Best ResponseYou've already chosen the best response.1yes 7 x^2 so far you have \[ 7x^2 3x6x8 \] now how many of the x's

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.02 x's because 3x and 6x right

phi
 3 years ago
Best ResponseYou've already chosen the best response.1it is 3x 6x we could "factor out" the x to get (36) x now what is 36 ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0is the 6 a negative too

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if the six is negative it be 9 right

phi
 3 years ago
Best ResponseYou've already chosen the best response.1yes 36 is 9 so the answer is 9x the whole answer is \[ 7x^2 9x8 \] if negative numbers are unclear, see http://www.khanacademy.org/math/arithmetic/absolutevalue/adding_subtracting_negatives/v/negativenumbersintroduction
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