Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

XavierBest ResponseYou've already chosen the best response.0
With ln(x) in the denominator like that that's not one of our preatty integrals.
 one year ago

satellite73Best ResponseYou've already chosen the best response.2
you will not find a nice closed form for this one
 one year ago

dan815Best ResponseYou've already chosen the best response.0
is it one of those repeating integrating ones
 one year ago

satellite73Best ResponseYou've already chosen the best response.2
you mean like if you integrate by parts will you go around in a circle? i don't think so
 one year ago

satellite73Best ResponseYou've already chosen the best response.2
i think you will not be able to solve in in the sense that you will not be able to find some nice function \(F\) whose derivative is \(\frac{x}{\ln(x)}\)
 one year ago

XavierBest ResponseYou've already chosen the best response.0
It's the type where our general methods of integrating get us nowhere. We have to leave it in the form of an integral and work with it that way.
 one year ago

dan815Best ResponseYou've already chosen the best response.0
this is what im trying to evaultate dw:1363059332628:dw
 one year ago

dan815Best ResponseYou've already chosen the best response.0
is there another method to equate integral like i know this isnt conservative so
 one year ago

XavierBest ResponseYou've already chosen the best response.0
That's completly different. If you are integrating with repect to y first then you don't need to worry about the expressions in x  they are essentially constants.
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.0
Wolfram says it's not expressible in terms of elementary functions  http://www.wolframalpha.com/input/?i=integrate+x%2Fln+x
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.0
imo you'd best be off solving it numerically
 one year ago

dan815Best ResponseYou've already chosen the best response.0
oh hold on i think i got it xD i forgot the lnx cancels if i do dy first
 one year ago

dan815Best ResponseYou've already chosen the best response.0
xavier u got some time to help ?? im working on one of my assigments due in about 6 hours, gonna need help when i get stuck
 one year ago

XavierBest ResponseYou've already chosen the best response.0
I'm here on and off. I'll try to help. Sure other people will jump onboard if I take too long
 one year ago

dan815Best ResponseYou've already chosen the best response.0
just looking thru the questions so far i think im gonna just have some trouble in the volume integral questions ill tell ya when i get to them
 one year ago

dan815Best ResponseYou've already chosen the best response.0
look at this one its about setting the right bounds dw:1363060518856:dw
 one year ago

dan815Best ResponseYou've already chosen the best response.0
i get why for dx its y^2 to 4 but how much for dy just doing 0 to 2 instead is enough how come it cant be be rootX to 4
 one year ago

XavierBest ResponseYou've already chosen the best response.0
What is correct there? The diagram or the bounds on your integrals?
 one year ago

dan815Best ResponseYou've already chosen the best response.0
the whole thing is correct i just need to covert to an another double integration where im doing it in reverse order dy dx
 one year ago

dan815Best ResponseYou've already chosen the best response.0
but before i do that i wanna know why they set up bounds like that
 one year ago

XavierBest ResponseYou've already chosen the best response.0
Either the bounds are wrong or the shaded area is incorrect. Having \[y^2 \le x \le 4\] is the larger of the two areas there.
 one year ago

dan815Best ResponseYou've already chosen the best response.0
the shaded region is what im integrating over its in the bounds the function is just like a force equation
 one year ago

XavierBest ResponseYou've already chosen the best response.0
Then your bounds on x should be \[0 \le x \le y^2\]
 one year ago

dan815Best ResponseYou've already chosen the best response.0
oh nvm i see what u mean the diagram is wrong
 one year ago

dan815Best ResponseYou've already chosen the best response.0
so the bottom part shud be the shaded region right
 one year ago

XavierBest ResponseYou've already chosen the best response.0
Ah ok so you know that the curve your have is y^2=x or y=sqrt(x). So y is bounded above by sqrt(x) and below by 0. And x ranges from 0 to 4
 one year ago

dan815Best ResponseYou've already chosen the best response.0
so if i wanted to switch order of integration to dy dx then
 one year ago

XavierBest ResponseYou've already chosen the best response.0
Just use the bounds on y on the inner integral. x bounds go on outer integral \[0 \le y \le \sqrt{x}\ ; 0 \le x \le 4\]
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.