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See the attachment

please just solve this Question

plz buddy solve this i don't have any idea how to solve..

you could start by writing down
I-A
can you do that ?

yes i did

I have problem with that equation in the circle i shown.

call 2 sin^2(a/2) = x
then it looks like 1-x+x

**look at the top left expression. Doesn't that simplify?

:( not understand

or are you asking how they got to that point ?

yes

that's Eq^n 1st

the matrix above the circled stuff....

hmm

can we write \[\cos \alpha/2 = (1-\tan ^{2} \alpha/2) / (1+\tan^{2} \alpha/2)\]

sorry ** its \[\cos \alpha \]

can I say something?

yes please .. @hoa

i just do the first term:

that's correct i already done this

a11= cos + tanalpha/2* sin= 1

you can expand the term like what phi says and you get 1 exactly what the left side matrix is

Just last Query ... how both that matrix same ?

they are a block and calculate together.

Can you follow that?

ok i done

@phi i can also use this cos(2a)=1-tan^2a/1+tan^2a

ok you can solve this using this identity

It does not look like a fruitful way to proceed, as you have sin and cos

No we can do using that Eq too

i'll show it to you in morning :)