Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Factor completely: 9c3d2 − 6cd3 3cd2(3c − 2d) 3cd(3c2 − 2d2) 3c2d(3c − 2d2) 3cd2(3c2 − 2d)

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
what do they have in common?
2 - 2d
meaning...what can you take out of both sides? are both 6 and 9 divisable by 3?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

no idea
can 3 go into both 6 and 9 evenly? yes they can so we can factor a 3 out..... is there at least 1 "u" in each side?
i meant "c" sorry
there is at least 1 "c" in each side....there is at least 1 "d" in each side...so all can be factored out (moved out of the parenthesis) so we have 3cd(3c²d - 2d²) huh...look we still have at least 1 "d" in each side ...so we can factor out another "d" 3cd²(3c² - 2d) which option choice is that?
ima go with the last one
and you are correct :) but do you understand it?
i think so.
thank u :)
anytime :) and if you need more explaination....feel free to message me a question and I'll try to explain it in a bit more detail :)
::)

Not the answer you are looking for?

Search for more explanations.

Ask your own question