Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

ChristineToTheRescue Group TitleBest ResponseYou've already chosen the best response.0
dw:1363121278806:dw Looks like this, right?
 one year ago

ChristineToTheRescue Group TitleBest ResponseYou've already chosen the best response.0
So basically, We begin by factoring the denominator.
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
\[\large \frac{x5}{x^2+2x3} \qquad = \qquad \frac{x5}{(x1)(x+3)}\]Understand how that factors? Ok the next step is to split up those factors in the denominator. It will look like this.\[\large \frac{x5}{(x1)(x+3)} \qquad = \qquad \frac{A}{x1}+\frac{B}{x+3}\]Where A and B are some unknown constants.
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Multiply both sides by the denominator on the left.\[\large \cancel{(x1)}\cancel{(x+3)}\frac{x5}{\cancel{(x1)}\cancel{(x+3)}} \qquad = \\ \qquad \frac{A}{\cancel{x1}}\cancel{(x1)}(x+3)+\frac{B}{\cancel{x+3}}(x1)\cancel{(x+3)}\] Leaving us with,\[\large x5=A(x+3)+B(x1)\]
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Then solve for A and B by `equating like terms`. Then plug the A and B back into this,\[\large \frac{A}{x1}+\frac{B}{x+3}\]And that's it! :D
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.