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yashar806

  • one year ago

help please.

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  1. Chris123456789
    • one year ago
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    with what?

  2. yashar806
    • one year ago
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  3. satellite73
    • one year ago
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    what is "inter quartile range" does it mean the middle half?

  4. satellite73
    • one year ago
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    we can do this

  5. satellite73
    • one year ago
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    the area of that triangle on the right is 1, because the area has to be one therefore the height is \(\frac{1}{4}\)

  6. yashar806
    • one year ago
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    how?

  7. yashar806
    • one year ago
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    how did you get height 1/4?

  8. satellite73
    • one year ago
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    i mean on the left, not on the right, but i just noticed that we do not have to even calculate it, just say if it is bigger or less than 4

  9. satellite73
    • one year ago
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    i got \(\frac{1}{4}\) as the height because the total area has to be one, and the area of a triangle is \(\frac{1}{2}bh\) in this case the base is 8 so the height must be \(\frac{1}{4}\)

  10. satellite73
    • one year ago
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    it doesn't matter anyway, because you don't actually have to compute it, you just have to say if it is larger or smaller than 4 and it is clearly smaller

  11. satellite73
    • one year ago
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    this is more than half the area |dw:1363143091389:dw|

  12. satellite73
    • one year ago
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    for the one on the right the interquartile range will be larger than 4, because the area between 2 and 6 is clearly less than half the total area

  13. satellite73
    • one year ago
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    this is less than half the area |dw:1363143276106:dw|

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