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appleduardoBest ResponseYou've already chosen the best response.0
so far i have:\[x(arcsinx)\int\limits_{}^{}x \frac{ 1 }{ \sqrt{1x^2} }dx\]
 one year ago

KainuiBest ResponseYou've already chosen the best response.2
Looks like you've done most of the hard part. Now take 1x^2 and integrate by subtitution.
 one year ago

appleduardoBest ResponseYou've already chosen the best response.0
uhmm how can i do that?
 one year ago

appleduardoBest ResponseYou've already chosen the best response.0
there's where i got confused!
 one year ago

dumbcowBest ResponseYou've already chosen the best response.0
trig substitution x = sin(u) dx = cos(u) du
 one year ago

KainuiBest ResponseYou've already chosen the best response.2
So take (1x^2)=u and take the derivative with respect to x, this becomes 2x=du/dx which can be rearranged with algebra into: xdx=(1/2)du Substitution back into the original integrand gives: \[\int\limits_{}^{}\frac{ du }{ 2\sqrt{u} } = \frac{ 1 }{ 2 }\int\limits_{}^{}\ u^{1/2} du\]
 one year ago

KainuiBest ResponseYou've already chosen the best response.2
@dumbcow trig substitution isn't really useful here.
 one year ago
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