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andu1854

  • 3 years ago

Verify the Identity: (tan x + tan y)/(cot x + cot y) = (tan x tan y - 1 ) / (1-cot x cot y )

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  1. jishan
    • 3 years ago
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    lhs= tanx+ tany/cotx+coty=tanx.tany rhs= tanx.tany-1/1-cotx.coty=tanx.tany

  2. andu1854
    • 3 years ago
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    Thank you, for the help, however, I am still trying to solve it... the goal is to show the steps how the left side will equal the right side. I decided to convert tan to cos/sin and got stuck. Attempted to use tan and cot and got even more stuck. I am interested to see what I am doing wrong... Here is a PDF of what I attempted.. and the equation... I need to verify... [(tanx+tany)/(\cot x+\cot y) = (\tan x \tan y-1) / (1 -\cot x \cot y\]

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  3. dhanamkoilraj
    • 3 years ago
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    @andu1854 your second step is wrong

  4. andu1854
    • 3 years ago
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    yes, I actually started over and was able to get tan x tan y =, but I was not sure how to set up the double angle for tan, unlike for sin & cos...

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