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andu1854
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Verify the Identity: (tan x + tan y)/(cot x + cot y) = (tan x tan y  1 ) / (1cot x cot y )
 one year ago
 one year ago
andu1854 Group Title
Verify the Identity: (tan x + tan y)/(cot x + cot y) = (tan x tan y  1 ) / (1cot x cot y )
 one year ago
 one year ago

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jishan Group TitleBest ResponseYou've already chosen the best response.0
lhs= tanx+ tany/cotx+coty=tanx.tany rhs= tanx.tany1/1cotx.coty=tanx.tany
 one year ago

andu1854 Group TitleBest ResponseYou've already chosen the best response.0
Thank you, for the help, however, I am still trying to solve it... the goal is to show the steps how the left side will equal the right side. I decided to convert tan to cos/sin and got stuck. Attempted to use tan and cot and got even more stuck. I am interested to see what I am doing wrong... Here is a PDF of what I attempted.. and the equation... I need to verify... [(tanx+tany)/(\cot x+\cot y) = (\tan x \tan y1) / (1 \cot x \cot y\]
 one year ago

dhanamkoilraj Group TitleBest ResponseYou've already chosen the best response.0
@andu1854 your second step is wrong
 one year ago

andu1854 Group TitleBest ResponseYou've already chosen the best response.0
yes, I actually started over and was able to get tan x tan y =, but I was not sure how to set up the double angle for tan, unlike for sin & cos...
 one year ago
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