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yashar806

  • one year ago

Help with probability

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  1. yashar806
    • one year ago
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  2. hartnn
    • one year ago
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    sum of all probabilities must equal 1. so, add them and equate it to 1 but there are 2 values unknown.,.....

  3. ParthKohli
    • one year ago
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    The sum of all probabilities must be __

  4. hartnn
    • one year ago
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    with only one equation

  5. yashar806
    • one year ago
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    yeah, that's why I get confused

  6. hartnn
    • one year ago
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    if any one of the ??? was given, then you could have found out other ???

  7. yashar806
    • one year ago
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    answer is b , but i dont know why?

  8. hartnn
    • one year ago
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    :O

  9. ParthKohli
    • one year ago
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    Impossibru!

  10. hartnn
    • one year ago
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    i would have gone with D

  11. yashar806
    • one year ago
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    but actually answer is B

  12. ParthKohli
    • one year ago
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    The answer would be B if and only if the probability of getting A+, A, B+ and B is equal to the probability of getting C+, C, D, F. But that is not given in the question, so I'd go with Hartnn.

  13. ParthKohli
    • one year ago
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    That is, 0.5

  14. hartnn
    • one year ago
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    oh wait its possible :P

  15. hartnn
    • one year ago
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    C+ or better = 1- (C or D or E)

  16. hartnn
    • one year ago
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    P (C+ or better) = 1-P (C or D or E)) =1- (0.22+0.09+0.07)

  17. yashar806
    • one year ago
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    why we choose c ,d, e ?

  18. hartnn
    • one year ago
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    sorry, C,D,F

  19. yashar806
    • one year ago
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    yeahh, but why?

  20. hartnn
    • one year ago
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    C+ or better means A+ to C+ if we add all probabilities, we get =1 so, A+ to F = 1 (A+ to C+) + (C,D,F) =1 so, (A+to C+) = 1- (C,D,F)

  21. yashar806
    • one year ago
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    oh, I got it , thank you very much

  22. hartnn
    • one year ago
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    welcome ^_^

  23. hartnn
    • one year ago
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    ^ that.is.incorrect.

  24. hartnn
    • one year ago
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    because you don't want 5 out of 8, you need probabilities of C+ or better, which needs individual probabilities. you haven't used any of the probabilities given. also, 0.62 is different from 0.625

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