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aussy123

  • 2 years ago

How do I solve this problem? Solve for cosθ in sin^2θ + cos^2θ = 1

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  1. terenzreignz
    • 2 years ago
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    This? \[\large \sin^2\theta+\cos^2\theta=1\]

  2. aussy123
    • 2 years ago
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    yes

  3. terenzreignz
    • 2 years ago
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    Well, let's see... How to break this to you... cosθ can literally be any value from [-1 , 1] Let me explain... the value of cosθ depends on the value of θ, right?

  4. aussy123
    • 2 years ago
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    yes

  5. terenzreignz
    • 2 years ago
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    Well, unfortunately (fortunately?) ANY value of θ would make this statement true sin²θ + cos²θ = 1

  6. hartnn
    • 2 years ago
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    he/she needs to solve for cos so, subtract sin^2 term from both sides, what u get ?

  7. terenzreignz
    • 2 years ago
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    Oops... Must have been overexcited :) My bad

  8. aussy123
    • 2 years ago
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    Im trying to write it but its giving me a hard time

  9. aussy123
    • 2 years ago
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    ±√(1 + sin2Θ)

  10. hartnn
    • 2 years ago
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    did you mean \(\pm \sqrt{1-\sin^2 \theta}\) ??

  11. aussy123
    • 2 years ago
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    yes I pasted the wrong one Sorry, my computer is acting really crazy today

  12. hartnn
    • 2 years ago
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    ohh..if you meant that, then you are correct.

  13. aussy123
    • 2 years ago
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    ok thanks you made this very easy, thank you.. :)

  14. hartnn
    • 2 years ago
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    glad to hear :) welcome ^_^

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