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aussy123
Group Title
How do I solve this problem?
Solve for cosθ in sin^2θ + cos^2θ = 1
 one year ago
 one year ago
aussy123 Group Title
How do I solve this problem? Solve for cosθ in sin^2θ + cos^2θ = 1
 one year ago
 one year ago

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terenzreignz Group TitleBest ResponseYou've already chosen the best response.0
This? \[\large \sin^2\theta+\cos^2\theta=1\]
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.0
Well, let's see... How to break this to you... cosθ can literally be any value from [1 , 1] Let me explain... the value of cosθ depends on the value of θ, right?
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.0
Well, unfortunately (fortunately?) ANY value of θ would make this statement true sin²θ + cos²θ = 1
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
he/she needs to solve for cos so, subtract sin^2 term from both sides, what u get ?
 one year ago

terenzreignz Group TitleBest ResponseYou've already chosen the best response.0
Oops... Must have been overexcited :) My bad
 one year ago

aussy123 Group TitleBest ResponseYou've already chosen the best response.1
Im trying to write it but its giving me a hard time
 one year ago

aussy123 Group TitleBest ResponseYou've already chosen the best response.1
±√(1 + sin2Θ)
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
did you mean \(\pm \sqrt{1\sin^2 \theta}\) ??
 one year ago

aussy123 Group TitleBest ResponseYou've already chosen the best response.1
yes I pasted the wrong one Sorry, my computer is acting really crazy today
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
ohh..if you meant that, then you are correct.
 one year ago

aussy123 Group TitleBest ResponseYou've already chosen the best response.1
ok thanks you made this very easy, thank you.. :)
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
glad to hear :) welcome ^_^
 one year ago
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