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anonymous
 3 years ago
secθ/cosθ can not be written as
1/cos2Θ
cos2Θ
sec2Θ > I know it can be written as this, but Im not sure about the other two
anonymous
 3 years ago
secθ/cosθ can not be written as 1/cos2Θ cos2Θ sec2Θ > I know it can be written as this, but Im not sure about the other two

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0im pretty sure its the first one

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I thought that too, but my friend said it was wrong.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well sec is 1/cos and cos is cos/1 so i dont see how cos can end up in the denominator..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Ill get another opinion too @hartnn

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thats exactly what I said but she confused me

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0smart choice, sorry i cant help better :/ all i know is that sec is 1/cos and cos is cos over 1 so technically they would cancel each other out..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thanks Ill try that one anyway!! :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0haha good plan :) just dont blame me if its wrong!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Haha it was wrong, but its all good, I still made a 90.9 grade, That was the only answer I had wrong. Thank you for your time and consideration :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0awhh im sorry! which one was it then, haha. Anytime, just message me or mention me in a question you have and ill be happy to help :)

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.0sec x = 1/ cos x .....so. cos x =1/sec x also sec x /(1/sec x ) = sec^2 x and (1/cos x)/cos x = 1/cos^2 x so, it can be written as sec^2 x or 1/cos^2 x but not cos^2 x i know it doesn't affect your score now, but i wanted you to know the standard relation, sec x=1/cos x
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