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yashar806
 2 years ago
Probability
yashar806
 2 years ago
Probability

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yashar806
 2 years ago
Best ResponseYou've already chosen the best response.0The following five games are scheduled to be played at the World curling championship one morning. The values in parentheses are the probabilities of each team winning their respective game. Game 1: Finland vs Germany Game 2:USA vs Switzerland Game3:Japan vs Canada Game4:Denmark vs Sweden Game 5:France vs Scotland The outcome of interest is the winners of the five games.how many out comes are contained in the sample space?

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0there are no paranthesised values

yashar806
 2 years ago
Best ResponseYou've already chosen the best response.00.43 vs 0.57 0.28vs 0.72 0.11vs 0.89 0.33vs o.67 0.18vs 0.82

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0assuming each game can only have one winner ... and he outcome of interest is the winners of the five games. a.b > a c.d > c e.f > e g.h > g i .j > i which leads one to believe that the set of outcomes has a cardinality of 5 is there something else to the setup that we might be overlooking?

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0it might be asking, of the 10 teams, how many ways are there to choose 5 winners? (10P5)/5! 10.9.8.7.6  5.4.3.2 2.9.7.2 ; .... is greater than 32 so its not that

yashar806
 2 years ago
Best ResponseYou've already chosen the best response.0What is the probability that at least one underdog wins?

yashar806
 2 years ago
Best ResponseYou've already chosen the best response.0Underdog is the team who is less likely to win

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0i dont know the rules of how winners are paired up with losers ... so i cant even begin to make an educated run at this

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0you have 5 teams in the running, 4 teams get paired up with a 1 team in the wings .... to do what? there is either assumed knowledge that is not present, or missing information that i cant deduce.

yashar806
 2 years ago
Best ResponseYou've already chosen the best response.0The favourite is the team with the higher probability of winning

yashar806
 2 years ago
Best ResponseYou've already chosen the best response.0Underdog is the team who is less likely to win

yashar806
 2 years ago
Best ResponseYou've already chosen the best response.0What is the probability that at least one underdog wins?

yashar806
 2 years ago
Best ResponseYou've already chosen the best response.0That's what all the question asking about

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0thats doesnt really help me out in determining anything past the first round of winners and losers

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0in any case, this question makes no sense to me so im not going to be of any use in solving it .... good luck

yashar806
 2 years ago
Best ResponseYou've already chosen the best response.0I have included the relevant numbers for each team

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0yes you have, and they still dont help me sort anything out ....

tomo
 2 years ago
Best ResponseYou've already chosen the best response.2C(2,1)*C(2,1)*C(2,1)*C(2,1)*C(2,1) = 2^5 = 32

yashar806
 2 years ago
Best ResponseYou've already chosen the best response.0What is the probability that at least one underdog wins?

yashar806
 2 years ago
Best ResponseYou've already chosen the best response.0What are the non underdog wins?

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0it almost sounds like a decision tree model http://www.bus.utk.edu/stat/datamining/Decision%20Trees%20for%20Predictive%20Modeling%20(Neville).pdf

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0i see the 32 from 5 cases in there

tomo
 2 years ago
Best ResponseYou've already chosen the best response.2Game 1: Finland vs Germany Game 2:USA vs Switzerland Game3:Japan vs Canada Game4:Denmark vs Sweden Game 5:France vs Scotland 0.43 vs 0.57 0.28 vs 0.72 0.11 vs 0.89 0.33 vs 0.67 0.18 vs 0.82 since they are independent P(A AND B) = P(A)*P(B) you want 1[P(germany wins AND switzerland wins AND canda wins AND sweden wins AND scotland wins)] = 1P(germany wins)*P(switzerland wins) *P(canada wins) * P(sweden wins) * P(scotland wins) = 1(.57*.72*.89*.67*.82) = 0.7993283536

kropot72
 2 years ago
Best ResponseYou've already chosen the best response.0Each game has 2 possible outcomes. The sample space is 2^5 = 32

yashar806
 2 years ago
Best ResponseYou've already chosen the best response.0I see thank you very much tomo
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