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yashar806Best ResponseYou've already chosen the best response.0
The following five games are scheduled to be played at the World curling championship one morning. The values in parentheses are the probabilities of each team winning their respective game. Game 1: Finland vs Germany Game 2:USA vs Switzerland Game3:Japan vs Canada Game4:Denmark vs Sweden Game 5:France vs Scotland The outcome of interest is the winners of the five games.how many out comes are contained in the sample space?
 one year ago

yashar806Best ResponseYou've already chosen the best response.0
But I don't know how
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
there are no paranthesised values
 one year ago

yashar806Best ResponseYou've already chosen the best response.0
0.43 vs 0.57 0.28vs 0.72 0.11vs 0.89 0.33vs o.67 0.18vs 0.82
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
assuming each game can only have one winner ... and he outcome of interest is the winners of the five games. a.b > a c.d > c e.f > e g.h > g i .j > i which leads one to believe that the set of outcomes has a cardinality of 5 is there something else to the setup that we might be overlooking?
 one year ago

yashar806Best ResponseYou've already chosen the best response.0
But the answer is 32
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
it might be asking, of the 10 teams, how many ways are there to choose 5 winners? (10P5)/5! 10.9.8.7.6  5.4.3.2 2.9.7.2 ; .... is greater than 32 so its not that
 one year ago

yashar806Best ResponseYou've already chosen the best response.0
What is the probability that at least one underdog wins?
 one year ago

yashar806Best ResponseYou've already chosen the best response.0
Underdog is the team who is less likely to win
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
i dont know the rules of how winners are paired up with losers ... so i cant even begin to make an educated run at this
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
you have 5 teams in the running, 4 teams get paired up with a 1 team in the wings .... to do what? there is either assumed knowledge that is not present, or missing information that i cant deduce.
 one year ago

yashar806Best ResponseYou've already chosen the best response.0
The favourite is the team with the higher probability of winning
 one year ago

yashar806Best ResponseYou've already chosen the best response.0
Underdog is the team who is less likely to win
 one year ago

yashar806Best ResponseYou've already chosen the best response.0
What is the probability that at least one underdog wins?
 one year ago

yashar806Best ResponseYou've already chosen the best response.0
That's what all the question asking about
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
thats doesnt really help me out in determining anything past the first round of winners and losers
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
in any case, this question makes no sense to me so im not going to be of any use in solving it .... good luck
 one year ago

yashar806Best ResponseYou've already chosen the best response.0
I have included the relevant numbers for each team
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
yes you have, and they still dont help me sort anything out ....
 one year ago

tomoBest ResponseYou've already chosen the best response.2
C(2,1)*C(2,1)*C(2,1)*C(2,1)*C(2,1) = 2^5 = 32
 one year ago

yashar806Best ResponseYou've already chosen the best response.0
What is the probability that at least one underdog wins?
 one year ago

yashar806Best ResponseYou've already chosen the best response.0
What are the non underdog wins?
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
it almost sounds like a decision tree model http://www.bus.utk.edu/stat/datamining/Decision%20Trees%20for%20Predictive%20Modeling%20(Neville).pdf
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
i see the 32 from 5 cases in there
 one year ago

tomoBest ResponseYou've already chosen the best response.2
Game 1: Finland vs Germany Game 2:USA vs Switzerland Game3:Japan vs Canada Game4:Denmark vs Sweden Game 5:France vs Scotland 0.43 vs 0.57 0.28 vs 0.72 0.11 vs 0.89 0.33 vs 0.67 0.18 vs 0.82 since they are independent P(A AND B) = P(A)*P(B) you want 1[P(germany wins AND switzerland wins AND canda wins AND sweden wins AND scotland wins)] = 1P(germany wins)*P(switzerland wins) *P(canada wins) * P(sweden wins) * P(scotland wins) = 1(.57*.72*.89*.67*.82) = 0.7993283536
 one year ago

kropot72Best ResponseYou've already chosen the best response.0
Each game has 2 possible outcomes. The sample space is 2^5 = 32
 one year ago

yashar806Best ResponseYou've already chosen the best response.0
I see thank you very much tomo
 one year ago
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