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yashar806
Probability
The following five games are scheduled to be played at the World curling championship one morning. The values in parentheses are the probabilities of each team winning their respective game. Game 1: Finland vs Germany Game 2:USA vs Switzerland Game3:Japan vs Canada Game4:Denmark vs Sweden Game 5:France vs Scotland The outcome of interest is the winners of the five games.how many out comes are contained in the sample space?
there are no paranthesised values
0.43 vs 0.57 0.28vs 0.72 0.11vs 0.89 0.33vs o.67 0.18vs 0.82
assuming each game can only have one winner ... and he outcome of interest is the winners of the five games. a.b -> a c.d -> c e.f -> e g.h -> g i .j -> i which leads one to believe that the set of outcomes has a cardinality of 5 is there something else to the setup that we might be overlooking?
it might be asking, of the 10 teams, how many ways are there to choose 5 winners? (10P5)/5! 10.9.8.7.6 ----------- 5.4.3.2 2.9.7.2 ; .... is greater than 32 so its not that
What is the probability that at least one underdog wins?
Underdog is the team who is less likely to win
i dont know the rules of how winners are paired up with losers ... so i cant even begin to make an educated run at this
you have 5 teams in the running, 4 teams get paired up with a 1 team in the wings .... to do what? there is either assumed knowledge that is not present, or missing information that i cant deduce.
The favourite is the team with the higher probability of winning
Underdog is the team who is less likely to win
What is the probability that at least one underdog wins?
That's what all the question asking about
thats doesnt really help me out in determining anything past the first round of winners and losers
in any case, this question makes no sense to me so im not going to be of any use in solving it .... good luck
I have included the relevant numbers for each team
yes you have, and they still dont help me sort anything out ....
C(2,1)*C(2,1)*C(2,1)*C(2,1)*C(2,1) = 2^5 = 32
What is the probability that at least one underdog wins?
What are the non underdog wins?
it almost sounds like a decision tree model http://www.bus.utk.edu/stat/datamining/Decision%20Trees%20for%20Predictive%20Modeling%20(Neville).pdf
i see the 32 from 5 cases in there
Game 1: Finland vs Germany Game 2:USA vs Switzerland Game3:Japan vs Canada Game4:Denmark vs Sweden Game 5:France vs Scotland 0.43 vs 0.57 0.28 vs 0.72 0.11 vs 0.89 0.33 vs 0.67 0.18 vs 0.82 since they are independent P(A AND B) = P(A)*P(B) you want 1-[P(germany wins AND switzerland wins AND canda wins AND sweden wins AND scotland wins)] = 1-P(germany wins)*P(switzerland wins) *P(canada wins) * P(sweden wins) * P(scotland wins) = 1-(.57*.72*.89*.67*.82) = 0.7993283536
Each game has 2 possible outcomes. The sample space is 2^5 = 32
I see thank you very much tomo