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@experimentX how would i do this one?

let f(x) = sin(x)
then f'(x) = ?

okay

cos(x)

when is cos(x) zero?

zero? you said find the derivative of sinx right?

yes ... at what point is cos(x) equal to zero?

there is not point where it is equal to zero

why not?

when i graph it...it doesn't

you got the wrong graph then.

|dw:1363197320465:dw| thats how it looks liek ohh okay

|dw:1363197334937:dw|

ok

|dw:1363197397226:dw|

yea it is

okay i got it

so ... what's the point?

(0,1) ?

no ...

http://www.wolframalpha.com/input/?i=plot+cos%28x%29+from+-2pi+to+2pi

so its more than 1?

0,1.5 ?

NOOOOOOOOOOOOOOO
http://www.wolframalpha.com/input/?i=solve+cos%28x%29+%3D+0+for+x+between+0+and+pi

so its 1.57080?

|dw:1363198158808:dw|

ok

so pick any two points above pi/2 and below pi/2

okay? do you do this different than the las tone tho? i'm not gonna use f(a) - f(b)/ b - a ?

|dw:1363198343133:dw|

ohh ok

|dw:1363198401986:dw|

ok

|dw:1363198546707:dw|
do you get that?

yes i do

Okay i gotta go ...

ok thx

|dw:1363198676612:dw|

okay

So i filled in those a b c's and here i got....f(pi/2) = f(3pi/4) - f(pi/4) over 3pi/4 - pi/4

f(3pi/4) = 3pi^2 + 1 = ?

can u tell me if i plugged it right @experimentX ?

yes that's correct.

okay

I got 1

huh .. do it again, what is sin(pi/4) ... plug into wolfram.

hold on

1/sqrt(2)

i got 1 over sqrt of 2

what do i do next ?

yes ... plug into your Rolle's condition.

the formula right?

so f(1/sqrt(2) - f(1/sqrt(2)/ 1/sqrt(2) - 1/sqrt(2) ?

no ...

|dw:1363384214639:dw|

ohh ok

how do i solve that?

so it will be 3/3 right?

|dw:1363384415083:dw|

okay

so those will be the numerator?

yes ... you just found out the value. Do you know what is functional notation?

no

f(x) = 1

yep ...
if f(x) = sin(x) ,,, then what is f(pi/4) ??

1 over sqrt(2)

yes ... what is f(3pi/4) ??

its the same 1 over sqrt(2)

yes ... plug in those values in |dw:1363385976116:dw|

plug them in the denominator?

|dw:1363386098600:dw|

ohh okay hold on

f(1/sqrt(2) - f(1/sqrt(2) over 3pi/4 - pi/4

No no ... what are you dong?? why are you putting 1/sqrt(2) inside function?

you said to plug them in?

yes .. |dw:1363386528821:dw|

okay

i'll ask my teacher on this one thanks for your help.

|dw:1363387122187:dw|

so i plug those in pi?

no ... you just calculated those values. plug them in.

I just did and you told me it was incorrect..i'm confused

yes ... this is where you got confused.

ok

|dw:1363387985440:dw|

ohh ok

what is the value of|dw:1363388256685:dw|

0?

yes ... so |dw:1363388362361:dw|

the derivative of it?

yes ... is there a point where derivative is zero?

yea

what is that point?

umm at 0, 0?

No ..

idk

we talked about that in the above posts. check again ... the point is pi/2

ohh yes okay

so it reached 0 at pi/2

no ... the derivative is zero at pi/2

ok

gotta go ... you gotta work harder.

good luck!!

ok well can u tell me what i should do next before you go

you wanted to verify Rolle's theorem, which you did.

yea its continuos and differentiable i know that

what do you want to do?

find a value for c

so this could be true a < c < b

of course it is ..

|dw:1363389508215:dw|

ok so c is pi/2 ?

|dw:1363389556563:dw|

ohhh ok

so c is 2pi/4

yes

ok

any probs??

no thx

see you around ... gotta go offline :)

ok