## InsanelyChaotic 2 years ago What is the 9th term of the geometric sequence where a1 = -6 and a6 = -6,144? (1 points) Answer -327,680 -393,216 -458,752 -524,288

1. timo86m

a_n*r^n = nth term

2. InsanelyChaotic

ok please teach me how i set it up?

3. InsanelyChaotic

what do i put in for "n"?

4. timo86m

hold on i am on it.

5. timo86m

formula is off a bit formula is this a*r^(n-1) = nth term so first term is -6 cuzz if we plug it in a * r^( 1-1) = -6 ^ that is 0 a * r^0 =-6 ^ that is 1 cuzz anynumber to the 0th is 1 just a rule a=-6 so now we know a and plug it into the a6 6th term a *r^(n-1) = nth term -6 *r^(6-1) = -6144 -6 * r^5 = 6144 sfr r = -4 so now we have all variables a = - 6 and r is 4 so plug it into formula a*r^(n-1) = nth term -6*4^(9-1)= -393216

6. hartnn

the problem was that you solved it entirely by yourself @timo86m instead of making her solve...

7. InsanelyChaotic

no offense @timo86m but he's right... I don't learn that way

8. timo86m

The problem is that someone might not always be here for you so you need the answer for confirmation.