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InsanelyChaotic

  • one year ago

What is the 9th term of the geometric sequence where a1 = -6 and a6 = -6,144? (1 points) Answer -327,680 -393,216 -458,752 -524,288

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  1. timo86m
    • one year ago
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    a_n*r^n = nth term

  2. InsanelyChaotic
    • one year ago
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    ok please teach me how i set it up?

  3. InsanelyChaotic
    • one year ago
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    what do i put in for "n"?

  4. timo86m
    • one year ago
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    hold on i am on it.

  5. timo86m
    • one year ago
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    formula is off a bit formula is this a*r^(n-1) = nth term so first term is -6 cuzz if we plug it in a * r^( 1-1) = -6 ^ that is 0 a * r^0 =-6 ^ that is 1 cuzz anynumber to the 0th is 1 just a rule a=-6 so now we know a and plug it into the a6 6th term a *r^(n-1) = nth term -6 *r^(6-1) = -6144 -6 * r^5 = 6144 sfr r = -4 so now we have all variables a = - 6 and r is 4 so plug it into formula a*r^(n-1) = nth term -6*4^(9-1)= -393216

  6. hartnn
    • one year ago
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    the problem was that you solved it entirely by yourself @timo86m instead of making her solve...

  7. InsanelyChaotic
    • one year ago
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    no offense @timo86m but he's right... I don't learn that way

  8. timo86m
    • one year ago
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    The problem is that someone might not always be here for you so you need the answer for confirmation.

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