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timo86m

  • 3 years ago

I seen many problems like these here http://openstudy.com/study#/updates/5140bf27e4b0f08cbdc91cc0 put what if you where given third term is -96 and 6th term is -6144. its different cuzz you are not giving a as usual. how would you go about solving it? I am just thinking. You'd have to do some kind of system of equations right?

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  1. calmat01
    • 3 years ago
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    Correct. You would want to find d and a1 by knowing that a3=-96 , and thus n=3, and a6=-6144 and thus n=6.

  2. hartnn
    • 3 years ago
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    you would divide n'th term formulas for 3rd and 6th term this will give you common ratio=r then using any of the n'th term formula you can get 'a' also

  3. hartnn
    • 3 years ago
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    a3 = a1 r^2 a6 = a1 r^5 if you divide these 2, you get r^3 and hence 'r'

  4. hartnn
    • 3 years ago
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    then using a3 = a1 r^2 you can get a1 also

  5. calmat01
    • 3 years ago
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    oops, I did t again. I used arithmetic when I should have used geometric. Skip my posts, and go with hartnn's!

  6. jrod326
    • 3 years ago
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    monster truck?

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