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 one year ago
I seen many problems like these here
http://openstudy.com/study#/updates/5140bf27e4b0f08cbdc91cc0
put what if you where given third term is 96 and 6th term is 6144.
its different cuzz you are not giving a as usual.
how would you go about solving it? I am just thinking. You'd have to do some kind of system of equations right?
 one year ago
I seen many problems like these here http://openstudy.com/study#/updates/5140bf27e4b0f08cbdc91cc0 put what if you where given third term is 96 and 6th term is 6144. its different cuzz you are not giving a as usual. how would you go about solving it? I am just thinking. You'd have to do some kind of system of equations right?

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calmat01
 one year ago
Best ResponseYou've already chosen the best response.0Correct. You would want to find d and a1 by knowing that a3=96 , and thus n=3, and a6=6144 and thus n=6.

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1you would divide n'th term formulas for 3rd and 6th term this will give you common ratio=r then using any of the n'th term formula you can get 'a' also

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1a3 = a1 r^2 a6 = a1 r^5 if you divide these 2, you get r^3 and hence 'r'

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1then using a3 = a1 r^2 you can get a1 also

calmat01
 one year ago
Best ResponseYou've already chosen the best response.0oops, I did t again. I used arithmetic when I should have used geometric. Skip my posts, and go with hartnn's!
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