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InsanelyChaotic

  • one year ago

WHAT did I do wrong here? :( What is the 9th term of the geometric sequence where a1 = -6 and a6 = -6,144? First term: -6 Ratio: -1024 N= 9

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  1. InsanelyChaotic
    • one year ago
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    Did I mess up on the ratio part?

  2. hartnn
    • one year ago
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    yes :P

  3. InsanelyChaotic
    • one year ago
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    LOL let me revise

  4. hartnn
    • one year ago
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    can i tell you how can you get it ?

  5. InsanelyChaotic
    • one year ago
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    0.000097

  6. InsanelyChaotic
    • one year ago
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    -6 divided by (-6144)??

  7. timo86m
    • one year ago
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    i did this one for you

  8. hartnn
    • one year ago
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    no.... common ratio = next term/ previous term a1 and a6 are not consecutive terms

  9. InsanelyChaotic
    • one year ago
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    wait huh??? then what is???

  10. timo86m
    • one year ago
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    http://openstudy.com/study#/updates/5140bf27e4b0f08cbdc91cc0

  11. hartnn
    • one year ago
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    you'd find common ratio =r by, an = a1 r^{n-1} here, and only for this, n=6 a1=-6 always an=a6 =-6144

  12. InsanelyChaotic
    • one year ago
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    so n = 6 temporarily?

  13. hartnn
    • one year ago
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    yes, only to find the value of 'r'

  14. InsanelyChaotic
    • one year ago
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    ok:)

  15. InsanelyChaotic
    • one year ago
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    http://www.basic-mathematics.com/geometric-sequence-calculator.html

  16. InsanelyChaotic
    • one year ago
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    huh???????????/ ^

  17. hartnn
    • one year ago
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    don't use that.

  18. InsanelyChaotic
    • one year ago
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    Oh?

  19. hartnn
    • one year ago
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    plug in values in the formula and use other calculator or google.

  20. InsanelyChaotic
    • one year ago
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    okay

  21. InsanelyChaotic
    • one year ago
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    I don't know how to get this

  22. hartnn
    • one year ago
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    what u got after plugging in ?

  23. InsanelyChaotic
    • one year ago
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    First term: 625 Ratio: -6144 N= 9

  24. InsanelyChaotic
    • one year ago
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    I got numbers that were entirely off

  25. InsanelyChaotic
    • one year ago
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    in the 8 millions

  26. InsanelyChaotic
    • one year ago
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    8 thousands rather*

  27. InsanelyChaotic
    • one year ago
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    = -393,216

  28. hartnn
    • one year ago
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    ratio is not -6144 ratio = r is what you have to find

  29. InsanelyChaotic
    • one year ago
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    Really?????

  30. InsanelyChaotic
    • one year ago
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    ughhhh oh my god

  31. hartnn
    • one year ago
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    |dw:1363206281770:dw| did you get this step ?

  32. InsanelyChaotic
    • one year ago
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    no

  33. hartnn
    • one year ago
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    a1=-6 n=6 an=a6=-6144

  34. InsanelyChaotic
    • one year ago
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    ohhhh yes yes!!!

  35. InsanelyChaotic
    • one year ago
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    what do i do after the -6144

  36. hartnn
    • one year ago
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    you mean you want next step ? or right side of same step ?

  37. InsanelyChaotic
    • one year ago
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    the next step please:)

  38. InsanelyChaotic
    • one year ago
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    my notes are progressing!!

  39. hartnn
    • one year ago
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    |dw:1363206708125:dw| got this ?

  40. InsanelyChaotic
    • one year ago
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    -6144/ -6 ?

  41. InsanelyChaotic
    • one year ago
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    what is that loop thing?

  42. hartnn
    • one year ago
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    on right side ? its 'r' r^5

  43. InsanelyChaotic
    • one year ago
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    it looks like a deformed male genital

  44. hartnn
    • one year ago
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    lol :P

  45. InsanelyChaotic
    • one year ago
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    ohhhhhhhh!!!!!!! R

  46. hartnn
    • one year ago
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    yes, r = common ratio

  47. InsanelyChaotic
    • one year ago
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    got the step:)

  48. hartnn
    • one year ago
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    can you find 'r' from that ?

  49. InsanelyChaotic
    • one year ago
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    yes let me try

  50. InsanelyChaotic
    • one year ago
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    1024^5 = 1.1258999e+15

  51. hartnn
    • one year ago
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    its 1024 =r^5 not 1024^5

  52. InsanelyChaotic
    • one year ago
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    huh?

  53. hartnn
    • one year ago
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    \(1024 =r^5 \) taking 5th root on both sides, \(\large r= \sqrt[5]{1024}=..?\)

  54. InsanelyChaotic
    • one year ago
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    let me see

  55. InsanelyChaotic
    • one year ago
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    i dont know

  56. hartnn
    • one year ago
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    try this : \(r^5=1024=2^{10} \\ r^5= (2^2)^5 \implies r=2^2=4\)

  57. hartnn
    • one year ago
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    got how r=4 ?

  58. InsanelyChaotic
    • one year ago
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    yes

  59. hartnn
    • one year ago
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    good! so, now we have r=4 a1=-6 n=9 find an ?

  60. InsanelyChaotic
    • one year ago
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    no

  61. hartnn
    • one year ago
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    you can use that link.... or the formula

  62. InsanelyChaotic
    • one year ago
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    okay:) Ratio = 4?

  63. hartnn
    • one year ago
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    yes, common ratio = r= 4 is what we found out.

  64. InsanelyChaotic
    • one year ago
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    3603000625

  65. hartnn
    • one year ago
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    no...what values you put ?

  66. hartnn
    • one year ago
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    i got : The 9th term is -393216

  67. InsanelyChaotic
    • one year ago
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    I made a few minor errors but i fixed it

  68. hartnn
    • one year ago
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    great! any more doubts ?

  69. hartnn
    • one year ago
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    phew! this took an hour!

  70. InsanelyChaotic
    • one year ago
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    hahahh so so sorry!!!!!!!!!

  71. InsanelyChaotic
    • one year ago
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    you are literally THE BEST

  72. hartnn
    • one year ago
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    not really, but i'll take the compliment ;) Thanks :D

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