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Simplify the following expression: (5x2 + 3x + 4) − (2x2 + 5x − 1). If the final answer is written in the form Ax2 + Bx + C, what is the value of A? The 2 be hide 5x is squared and so is the one by 2x

Mathematics
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Distribute the negative
So -1?
I have terrible drawing skills, sorry.

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Other answers:

|dw:1363207136675:dw|
So 3x - 5 - 5x + 1
I meant:|dw:1363207208912:dw|
Very close. What is -1 times 1?
-1
Right! So your equation would be 3x - 5 - 5x - 1. Can you combine the like terms?
Yes. the x
Lets rearrange it so its easier to work with. Remember to keep the symbol in front of each term. 3x - 5x - 5 - 1 First off, what is 3x - 5x?
2x
-2x-6
Close, it would be a negative 2.
@GiGIgo3 please do not post direct answers. (:
Ok
So now we have: -2x - 5 - 1 -5 - 1 = ?
6
Negative 6. (: So our expression is: -2x - 6
Ok. Thanks!
You're welcome! Oh and:\[\Huge \mathcal{\text{Welcome To OpenStudy} ☺}\]
Thanks! can you help me some more
Sure thing!
Simplify the following expression: (5x2 + 3x + 4) − (2x2 + 5x − 1). If the final answer is written in the form Ax2 + Bx + C, what is the value of A?
The 2 be hide 5x is squared and so is the one by 2x
\[(5x^2 + 3x + 4) - (2x^2 + 5x - 1)\]We have to distribute the -1. \[(-1)\stackrel{\Huge\curvearrowright}(2x^2 + 5x - 1)\]-1 * 2x^1 = -2x^2 -1 * 5x = -5x -1 * -1 = 1 Now we have: \[5x^2 + 3x + 4 - 2x^2 - 5x + 1\]Combine like terms. 5x^2 - 2x^2 = 3x^2 3x - 5x = -2x 4 + 1 = 5 And we end up with: \[\large 3x^2 - 2x + 5\]
\[\large Ax^2 + Bx + C\] \[\large 3x^2 - 2x + 5 \] So what is A?
3x2
Just the 3. (:
Thanks! I have some more if that is ok?
I've gtg right now, sorry. :/ Maybe @hartnn or @Luis_Rivera can continue to help you. I hope I helped!
You did thanks!
one suggestion though, make new post for new question. so that many others can help you too :)
How do I do that?
you can 'close' this question .
Ok. Thanks
good ! :) welcome ^_^

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