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smiley2015

  • 3 years ago

Simplify the following expression: (5x2 + 3x + 4) − (2x2 + 5x − 1). If the final answer is written in the form Ax2 + Bx + C, what is the value of A? The 2 be hide 5x is squared and so is the one by 2x

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  1. ryan123345
    • 3 years ago
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    Distribute the negative

  2. smiley2015
    • 3 years ago
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    So -1?

  3. jazy
    • 3 years ago
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    I have terrible drawing skills, sorry.

  4. Claudilovely
    • 3 years ago
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    |dw:1363207136675:dw|

  5. smiley2015
    • 3 years ago
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    So 3x - 5 - 5x + 1

  6. jazy
    • 3 years ago
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    I meant:|dw:1363207208912:dw|

  7. jazy
    • 3 years ago
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    Very close. What is -1 times 1?

  8. smiley2015
    • 3 years ago
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    -1

  9. jazy
    • 3 years ago
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    Right! So your equation would be 3x - 5 - 5x - 1. Can you combine the like terms?

  10. smiley2015
    • 3 years ago
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    Yes. the x

  11. jazy
    • 3 years ago
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    Lets rearrange it so its easier to work with. Remember to keep the symbol in front of each term. 3x - 5x - 5 - 1 First off, what is 3x - 5x?

  12. smiley2015
    • 3 years ago
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    2x

  13. GiGIgo3
    • 3 years ago
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    -2x-6

  14. jazy
    • 3 years ago
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    Close, it would be a negative 2.

  15. jazy
    • 3 years ago
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    @GiGIgo3 please do not post direct answers. (:

  16. smiley2015
    • 3 years ago
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    Ok

  17. jazy
    • 3 years ago
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    So now we have: -2x - 5 - 1 -5 - 1 = ?

  18. smiley2015
    • 3 years ago
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    6

  19. jazy
    • 3 years ago
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    Negative 6. (: So our expression is: -2x - 6

  20. smiley2015
    • 3 years ago
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    Ok. Thanks!

  21. jazy
    • 3 years ago
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    You're welcome! Oh and:\[\Huge \mathcal{\text{Welcome To OpenStudy} ☺}\]

  22. smiley2015
    • 3 years ago
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    Thanks! can you help me some more

  23. jazy
    • 3 years ago
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    Sure thing!

  24. smiley2015
    • 3 years ago
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    Simplify the following expression: (5x2 + 3x + 4) − (2x2 + 5x − 1). If the final answer is written in the form Ax2 + Bx + C, what is the value of A?

  25. smiley2015
    • 3 years ago
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    The 2 be hide 5x is squared and so is the one by 2x

  26. jazy
    • 3 years ago
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    \[(5x^2 + 3x + 4) - (2x^2 + 5x - 1)\]We have to distribute the -1. \[(-1)\stackrel{\Huge\curvearrowright}(2x^2 + 5x - 1)\]-1 * 2x^1 = -2x^2 -1 * 5x = -5x -1 * -1 = 1 Now we have: \[5x^2 + 3x + 4 - 2x^2 - 5x + 1\]Combine like terms. 5x^2 - 2x^2 = 3x^2 3x - 5x = -2x 4 + 1 = 5 And we end up with: \[\large 3x^2 - 2x + 5\]

  27. jazy
    • 3 years ago
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    \[\large Ax^2 + Bx + C\] \[\large 3x^2 - 2x + 5 \] So what is A?

  28. smiley2015
    • 3 years ago
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    3x2

  29. jazy
    • 3 years ago
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    Just the 3. (:

  30. smiley2015
    • 3 years ago
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    Thanks! I have some more if that is ok?

  31. jazy
    • 3 years ago
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    I've gtg right now, sorry. :/ Maybe @hartnn or @Luis_Rivera can continue to help you. I hope I helped!

  32. smiley2015
    • 3 years ago
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    You did thanks!

  33. hartnn
    • 3 years ago
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    one suggestion though, make new post for new question. so that many others can help you too :)

  34. smiley2015
    • 3 years ago
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    How do I do that?

  35. hartnn
    • 3 years ago
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    you can 'close' this question .

  36. smiley2015
    • 3 years ago
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    Ok. Thanks

  37. hartnn
    • 3 years ago
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    good ! :) welcome ^_^

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