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mathstudent55Best ResponseYou've already chosen the best response.2
Think of it this way. The recatngle had an original length, L, and an original width, W. The new rectangle has a new length that is (2/3)L and a new width that is (2/3)W. You follow so far?
 one year ago

mathstudent55Best ResponseYou've already chosen the best response.2
Now let's find the area of the original rectangle and the area of the new rectangle. The area of a rectangle is length times width. The original rectangle: Aold = LW The new rectangle: Anew = (2/3)L * (2/3)W = (2/3)*(2/3)*LW = (4/9)LW
 one year ago

help123please.Best ResponseYou've already chosen the best response.1
Did you choose 4/9 randomly?
 one year ago

mathstudent55Best ResponseYou've already chosen the best response.2
Now you see that the new area is (4/9)LW and the old area is LW. That means the new area is 4/9 times the area of the old rectangle.
 one year ago

mathstudent55Best ResponseYou've already chosen the best response.2
No, 4/9 = 2/3 * 2/3
 one year ago

mathstudent55Best ResponseYou've already chosen the best response.2
Remember the problem states that the new rectangle has a length and width that are 2/3 what they used to be. So the new length is (2/3)L, and the new width is (2/3)W. When you multiply the new length and the new width to get the new area, you are multiplying (2/3)L * (2/3)W which is the same as (2/3)*(2/3)*LW. (2/3) * (2/3) = 4/9, so the new area is (4/9)LW
 one year ago

help123please.Best ResponseYou've already chosen the best response.1
OOOOOOH. Ok, I believe I understand it now  thank you.
 one year ago

mathstudent55Best ResponseYou've already chosen the best response.2
Then when you compare the new area of (4/9)LW with the original area of LW, you see that the new area is 4/9 of the old area.
 one year ago
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