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 one year ago
HELP PLEASE ???f ' (x) for a given function is (x2)/(x+3) and we are told that f (6) = 30. Write the equation of the tangent line to f(x) at x = 6 and use the tangent line equation to approximate the value of f (6.02).
 one year ago
HELP PLEASE ???f ' (x) for a given function is (x2)/(x+3) and we are told that f (6) = 30. Write the equation of the tangent line to f(x) at x = 6 and use the tangent line equation to approximate the value of f (6.02).

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Ephilo
 one year ago
Best ResponseYou've already chosen the best response.029.92 30.02 30.08 34.00 none of these

SithsAndGiggles
 one year ago
Best ResponseYou've already chosen the best response.0\[f(x)=\frac{x^2}{x+3}\Rightarrow f'(x)=\frac{x^2+6x}{(x+3)^2}\] The tangent line at x = 6 is given by \[yy_0=m(xx_0),\text{ where }(x_0,y_0)=(6,30),\text{ and }m=f'(6).\] You then use this equation to find an approximate value of f(6.02) by plugging in x = 6.02.
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