anonymous
  • anonymous
Probability
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
There are four patients on the neo-natal ward of a local hospital who are monitored by two staff members. Suppose the probability (at any one time) of a patient requiring attention by a sta member is 0.3. Assuming the patients behave independently, what is the probability at any one time that there will not be suffccient staff to attend to all patients who need them?
anonymous
  • anonymous
no time interval is mentioned, so my only guess is to solve having 3 or 4 patients need help
anonymous
  • anonymous
(A) 0.0756 (B) 0.1104 (C) 0.0837 (D) 0.0463 (E) 0.2646

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anonymous
  • anonymous
you are told that these are independent events, which is a set up for using the binomial probability
anonymous
  • anonymous
it is a multiple choice question
anonymous
  • anonymous
the probability that three will need it is \[P(x=3)=\binom{4}{3}(.3)^3(.7)\] and the probability that all four will need it is \[P(x=4)=.3^4\] add these up
anonymous
  • anonymous
of course \(\binom{4}{3}=4\)
anonymous
  • anonymous
you mean solve for that equation
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=4%28.3%29^3*.7%2B.3^4
anonymous
  • anonymous
ok, i got it thanks so much
anonymous
  • anonymous
it is not an equation, it is a computation requiring a calculator for sure
anonymous
  • anonymous
yw
anonymous
  • anonymous
sorry, where did you get that 3 ?
anonymous
  • anonymous
you mean when i wrote \(P(X=3)\) ?
anonymous
  • anonymous
is int 2?
anonymous
  • anonymous
yes
anonymous
  • anonymous
i was calculating the probability that 3 patients needed help
anonymous
  • anonymous
how.?
anonymous
  • anonymous
why three of them needed help/?
anonymous
  • anonymous
\[P(X=k)=\binom{n}{k}p^k(1-p)^{n-k}\]
anonymous
  • anonymous
there are two staff members and 4 patients if there are not enough staff members that means either 3 patients need help or 4 patients need help
anonymous
  • anonymous
oh, now I totally got it
anonymous
  • anonymous
the question asked "what is the probability at any one time that there will not be suffccient staff to attend to all patients who need them?"
anonymous
  • anonymous
ok thx
anonymous
  • anonymous
yw

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