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no time interval is mentioned, so my only guess is to solve having 3 or 4 patients need help

(A) 0.0756 (B) 0.1104 (C) 0.0837 (D) 0.0463 (E) 0.2646

you are told that these are independent events, which is a set up for using the binomial probability

it is a multiple choice question

of course \(\binom{4}{3}=4\)

you mean solve for that equation

http://www.wolframalpha.com/input/?i=4%28.3%29^3*.7%2B.3^4

ok, i got it thanks so much

it is not an equation, it is a computation
requiring a calculator for sure

yw

sorry, where did you get that 3 ?

you mean when i wrote \(P(X=3)\) ?

is int 2?

yes

i was calculating the probability that 3 patients needed help

how.?

why three of them needed help/?

\[P(X=k)=\binom{n}{k}p^k(1-p)^{n-k}\]

oh, now I totally got it

ok thx

yw