Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

mathcalculus Group Title

H-E-L-P : HOW TO FIND DERIVATIVE SQUARE ROOT OF 8-6*X^2

  • one year ago
  • one year ago

  • This Question is Closed
  1. mathcalculus Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\sqrt{8-6*X^2}\]

    • one year ago
  2. satellite73 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    the derivative of \(\sqrt{f(x)}\) is \[\frac{f'(x)}{2\sqrt{f(x)}}\]

    • one year ago
  3. mathcalculus Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    can we do this step by step please.

    • one year ago
  4. satellite73 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    the steps are what i wrote above take the derivative of \(8-6x^2\) and by the power rule, you get \(-12x\) that goes in the numerator in the denominator you put \(2\sqrt{8-6x^2}\)

    • one year ago
  5. mathcalculus Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    oh... why do we put that as the denominator?

    • one year ago
  6. satellite73 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    all that is left to do is cancel a 2 top and bottom

    • one year ago
  7. satellite73 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    the derivative of \(\sqrt{x}\) is \(\frac{1}{2\sqrt{x}}\) therefore by the chain rule the derivative of \(\frac{1}{f}\) is \(\frac{f'}{2\sqrt{f}}\) where \(f\) is any function

    • one year ago
  8. satellite73 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    for example, the derivative of \(\sqrt{\sin(x)}\) is \[\frac{\cos(x)}{2\sqrt{\sin(x)}}\]

    • one year ago
  9. satellite73 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    the derivative of \[\sqrt{3x^2+2x}\] is \[\frac{6x+2}{2\sqrt{3x^2+2x}}\]

    • one year ago
  10. mathcalculus Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    after i have -12x/ 2radical 8-6x^2.. how can i find the critical points?

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.