A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0\[\sqrt{86*X^2}\]

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0the derivative of \(\sqrt{f(x)}\) is \[\frac{f'(x)}{2\sqrt{f(x)}}\]

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0can we do this step by step please.

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0the steps are what i wrote above take the derivative of \(86x^2\) and by the power rule, you get \(12x\) that goes in the numerator in the denominator you put \(2\sqrt{86x^2}\)

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0oh... why do we put that as the denominator?

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0all that is left to do is cancel a 2 top and bottom

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0the derivative of \(\sqrt{x}\) is \(\frac{1}{2\sqrt{x}}\) therefore by the chain rule the derivative of \(\frac{1}{f}\) is \(\frac{f'}{2\sqrt{f}}\) where \(f\) is any function

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0for example, the derivative of \(\sqrt{\sin(x)}\) is \[\frac{\cos(x)}{2\sqrt{\sin(x)}}\]

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0the derivative of \[\sqrt{3x^2+2x}\] is \[\frac{6x+2}{2\sqrt{3x^2+2x}}\]

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0after i have 12x/ 2radical 86x^2.. how can i find the critical points?
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.