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Grazes
Group Title
Find f^1(x) and state any restrictions on the domain of f^1(x)
 one year ago
 one year ago
Grazes Group Title
Find f^1(x) and state any restrictions on the domain of f^1(x)
 one year ago
 one year ago

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Grazes Group TitleBest ResponseYou've already chosen the best response.0
\[f(x)=\frac{ x }{ x2 }\] \[x \neq 2 \]
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
you need the inverse?
 one year ago

Grazes Group TitleBest ResponseYou've already chosen the best response.0
Yes. I know I need to switch f(x) and x, but I dunno how you would simplify from there
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
you can take \[y=\frac{x}{x2}\] switch \(x\) and \(y\) to write \[x=\frac{y}{y2}\] and solve for \(y\)
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
you get \[x=\frac{y}{y2}\]\[x(y2)=y\] as a first step then multiply out
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
\[xy2x=y\] put the \(y\)'s on one side of the equal sign, the \(2x\) on the other \[xyy=2x\]
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
factor out the \(y\) on the left \[(x1)y=2x\]
 one year ago

Grazes Group TitleBest ResponseYou've already chosen the best response.0
Okay. I've got it from there
 one year ago

Grazes Group TitleBest ResponseYou've already chosen the best response.0
I didn't think to subtract y over ^^;;
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
and finally divide the domain will be all real numbers except \(x=1\) which is not surprising because that was the range of \(f\)
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
answer should be \[y=\frac{2x}{x1}\]
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
yeah you got to get the \(y\)' all on one side good luck
 one year ago
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