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Grazes
 2 years ago
Find f^1(x) and state any restrictions on the domain of f^1(x)
Grazes
 2 years ago
Find f^1(x) and state any restrictions on the domain of f^1(x)

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Grazes
 2 years ago
Best ResponseYou've already chosen the best response.0\[f(x)=\frac{ x }{ x2 }\] \[x \neq 2 \]

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0you need the inverse?

Grazes
 2 years ago
Best ResponseYou've already chosen the best response.0Yes. I know I need to switch f(x) and x, but I dunno how you would simplify from there

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0you can take \[y=\frac{x}{x2}\] switch \(x\) and \(y\) to write \[x=\frac{y}{y2}\] and solve for \(y\)

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0you get \[x=\frac{y}{y2}\]\[x(y2)=y\] as a first step then multiply out

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0\[xy2x=y\] put the \(y\)'s on one side of the equal sign, the \(2x\) on the other \[xyy=2x\]

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0factor out the \(y\) on the left \[(x1)y=2x\]

Grazes
 2 years ago
Best ResponseYou've already chosen the best response.0Okay. I've got it from there

Grazes
 2 years ago
Best ResponseYou've already chosen the best response.0I didn't think to subtract y over ^^;;

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0and finally divide the domain will be all real numbers except \(x=1\) which is not surprising because that was the range of \(f\)

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0answer should be \[y=\frac{2x}{x1}\]

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0yeah you got to get the \(y\)' all on one side good luck
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