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Grazes
 one year ago
Best ResponseYou've already chosen the best response.0\[f(x)=\frac{ x }{ x2 }\] \[x \neq 2 \]

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0you need the inverse?

Grazes
 one year ago
Best ResponseYou've already chosen the best response.0Yes. I know I need to switch f(x) and x, but I dunno how you would simplify from there

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0you can take \[y=\frac{x}{x2}\] switch \(x\) and \(y\) to write \[x=\frac{y}{y2}\] and solve for \(y\)

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0you get \[x=\frac{y}{y2}\]\[x(y2)=y\] as a first step then multiply out

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0\[xy2x=y\] put the \(y\)'s on one side of the equal sign, the \(2x\) on the other \[xyy=2x\]

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0factor out the \(y\) on the left \[(x1)y=2x\]

Grazes
 one year ago
Best ResponseYou've already chosen the best response.0Okay. I've got it from there

Grazes
 one year ago
Best ResponseYou've already chosen the best response.0I didn't think to subtract y over ^^;;

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0and finally divide the domain will be all real numbers except \(x=1\) which is not surprising because that was the range of \(f\)

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0answer should be \[y=\frac{2x}{x1}\]

satellite73
 one year ago
Best ResponseYou've already chosen the best response.0yeah you got to get the \(y\)' all on one side good luck
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