A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
HELPPPPPPP!!!! locate all critical points (both types) of
h(x)= radical 86*x^2
The critical point(s):
anonymous
 3 years ago
HELPPPPPPP!!!! locate all critical points (both types) of h(x)= radical 86*x^2 The critical point(s):

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I FOUND THE X WHICH IS 0. THEN I TRIED TO FIND Y BY PLUGGING IN ZERO BUT IT IS INCORRECT... :(

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i know the steps to this problem. which is find the derivative and i did...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0then = to zero. and i did that too. and I goy x but then im not sure how i got the answer wrong....

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.0It's hard to read the function when it's not formatted. Does this look accurate?\[\large h(x)=\sqrt{86x^2}\]Everything under the square root like that?

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.0Hmm so we get something like this, yes? \[\large h'(x)=\frac{6x}{\sqrt{86x^2}}\] So you determined that \(\large x=0\) is a critical point. There is also another. A critical point of the function also exists where \(\large f'(x)\) is undefined. (Assuming that value is included in the domain of \(\large f\).

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yeah I determined one critical point, but what about y?

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.0I'm saying that there is another critical point,\[\large \sqrt{86x^2}\]When this thing equals zero, we're dividing by zero, so f'(x) is undefined, DNE. \[\large 0=\sqrt{86x^2}\] Solve for x to find your other critical point(s).

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.0As for your y values, if you want to, you can plug x=0 into your original function, to find the corresponding y value. That will allow you to write it as an ordered pair if you want.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes i found 2 radical 2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and i wrote the answer like this... (0,2 radical 2)

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.0Hmm I think you end up with \(\large x=\pm \dfrac{2}{\sqrt3}\)

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.0\[\large 0=86x^2\]\[\large 8=6x^2\]\[\large \frac{8}{6}=x^2 \qquad \rightarrow \qquad \frac{4}{3}=x^2\]\[\large x=\pm \sqrt{\frac{4}{3}}\qquad \rightarrow \qquad x=\pm \frac{2}{\sqrt3}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0to find the critical points.. dont we find the derivative first?

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.0Yes, this was our derivative,\[\large h'(x)=\frac{6x}{\sqrt{86x^2}}\]We set the numerator equal to zero to find one critical point. We need to also set the denominator equal to zero to find the other(s). Which is what I was showing.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0we solve the denominator = to 0 but what about the radical we ignore it?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0have you used webwork?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0im not sure how to plug in the answer

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.0The square root? I squared both sides. 0^2 = 0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no the answer; how do we write it if there a positive and a negative 2 radical 3.

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.0I've used webassign, not webworks. Hmm Is there a panel on the left somewhere where you can use tools like sqrt?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the critical points are:

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ive tried every way but it's "Wrong"

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.0Write it as three separate critical points: (0, sqrt(8)) (2/sqrt(3),0) (2/sqrt(3),0) Does that work maybe? D:

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Operands of '*' are not of compatible types

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0because its between of (0, sqrt(8)) (2/sqrt(3),0) (2/sqrt(3),0)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hold on im so confused.... lol how did you get (0,8)

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.0We found that x=0 is a critical point. If we plug x=0 back into the original function it gives us, \(\large f(0)=\sqrt8\) right? We can write that as an ordered pair (0,sqrt(8))

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.0"Operands of '*' are not of compatible types" I don't understand what you're saying :o

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0not me, thats what webworks says..

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.0Does it tell you to list them as ordered pairs? Usually you just list critical points as x=

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Locate all critical points ( both types ) The critical point(s) is (are) . (The answers are to be points. Use parentheses in your answer(s). If there are no critical points, enter none .)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0now i tried to put the answer like this: (0,sqrt(8))U(2/sqrt(3),0)U(2/sqrt(3),0) but it says: Left endpoint must be less than right endpoint

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.0Hmm I'm not sure how your assignment wants them formatted. I would guess that you just separate them with commas. (0,sqrt(8)), (2/sqrt(3),0), (2/sqrt(3),0)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay, so after we find x, how do we get the + and  2 radical 3? i mean we plug in 0 to the original but i got 2 radical 2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i understand the 0 and sqrt 8 order pair...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0why couldnt i write 0, 2 radical 2 as a critical point?

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.0Scroll up to see my steps. I don't want to write them out again. Set the denominator equal to zero, solve for x.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0nvm but now... how about the +& 2 radical 3.

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.0We have an \(\large x^2\). When we take the root of a variable, we get two solutions, the positive and negative root.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i understand how you made the cal. but why did you ignore the radical and wrote it as 86x^2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes ,right. we have a postive and negative. i understand that but why did you ignore the radical and wrote it as 86x^2? when the original one had a radical .

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.0I didn't ignore the radical.\[\large 0=\sqrt{86x^2}\]Step 1, square both sides.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thank you so much! :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thank you thank you! ^_^

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i'll keep that the radicals need a + and  in mind.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.