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mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
first we find the derivative.. i know that.. then...?
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
then equate it to 0
 one year ago

jennychan12 Group TitleBest ResponseYou've already chosen the best response.0
set it = 0
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
but wait, im confused to find the derivative for this one..
 one year ago

jennychan12 Group TitleBest ResponseYou've already chosen the best response.0
chain rule/product rule
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
its 4(t1)^3 3(t+5)^2
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
what's next after it? i'm a little lost after it
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
4(t1)^3 3(t+5)^2 = 0
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
what about chain rule?
 one year ago

jennychan12 Group TitleBest ResponseYou've already chosen the best response.0
doesnt apply here because derviative of t is just 1
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
if ur function is of the type (t^2 + 2)^4 then s'(t) = 4 (t^2+2) * 2t
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
sorry s'(t) = 4 (t^2+2)^3 * 2t
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
oh right.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
so if the derivative of t is 1 then how do i solve t?
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
sorry imm not sure what to do after ... 4(t1)^3 3(t+5)^2
 one year ago
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