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mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0first we find the derivative.. i know that.. then...?

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0but wait, im confused to find the derivative for this one..

jennychan12
 one year ago
Best ResponseYou've already chosen the best response.0chain rule/product rule

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0its 4(t1)^3 3(t+5)^2

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0what's next after it? i'm a little lost after it

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0what about chain rule?

jennychan12
 one year ago
Best ResponseYou've already chosen the best response.0doesnt apply here because derviative of t is just 1

Yahoo!
 one year ago
Best ResponseYou've already chosen the best response.0if ur function is of the type (t^2 + 2)^4 then s'(t) = 4 (t^2+2) * 2t

Yahoo!
 one year ago
Best ResponseYou've already chosen the best response.0sorry s'(t) = 4 (t^2+2)^3 * 2t

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0so if the derivative of t is 1 then how do i solve t?

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0sorry imm not sure what to do after ... 4(t1)^3 3(t+5)^2
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