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mathcalculus
 2 years ago
find the critical points: s(t)= (t1)^4 (t+5)^3
mathcalculus
 2 years ago
find the critical points: s(t)= (t1)^4 (t+5)^3

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mathcalculus
 2 years ago
Best ResponseYou've already chosen the best response.0i found the derivative. 4(t1)^3 3(t+5)^2

kobesaurus
 2 years ago
Best ResponseYou've already chosen the best response.0is it just \[(t1)^4(t+5)^2\] ?

kobesaurus
 2 years ago
Best ResponseYou've already chosen the best response.0with the chain rule those are not the derivatives...

mathcalculus
 2 years ago
Best ResponseYou've already chosen the best response.0yes but instead of 2 as an exponent its 3. i know im suppose to = 0 then im not sure what to do.

kobesaurus
 2 years ago
Best ResponseYou've already chosen the best response.0wait that is right, t is single power, sorry.

mathcalculus
 2 years ago
Best ResponseYou've already chosen the best response.0okay so i did it wrong can we review step by step

kobesaurus
 2 years ago
Best ResponseYou've already chosen the best response.0just to be clear, it isnt the two equations plus one another, its them two multiplied by one another?

mathcalculus
 2 years ago
Best ResponseYou've already chosen the best response.0so i get.... 4(t1)^3 3(t+5)^2

kobesaurus
 2 years ago
Best ResponseYou've already chosen the best response.0(t1)^3 (t+5)^2 (17+7 t)

kobesaurus
 2 years ago
Best ResponseYou've already chosen the best response.0I'm trying to figure that out, I used Wolframalpha to check my work and it got something different.

Azteck
 2 years ago
Best ResponseYou've already chosen the best response.0Use the product rule!!! \[\huge s(t)= (t1)^4 (t+5)^3\] \[\huge s'(t)=4(t1)^3(t+5)^3+3(t+5)^2(t1)^4\] \[\huge =(t1)^3(t+5)^2[4t+20+3t3]\] \[\huge =(t1)^3(t+5)^2(7t+17)\] At S.P's s'(t)=0 \[\huge (t1)^3(t+5)^2(7t+17)=0\] \[\huge t=1, t=5, t=\frac{17}{7}\]

Azteck
 2 years ago
Best ResponseYou've already chosen the best response.0\[s(t)=y\] To find the values of y, sub in the values of t into the original equation.

Azteck
 2 years ago
Best ResponseYou've already chosen the best response.0Don't think you need to describe the nature of the curve [ie. Maximum or minimum turning point, etc.]. But I think you still need to find the inflection points of the function.

mathcalculus
 2 years ago
Best ResponseYou've already chosen the best response.0how did you get to this step: =(t−1)3(t+5)2[4t+20+3t−3]
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