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mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0i found the derivative. 4(t1)^3 3(t+5)^2

kobesaurus
 one year ago
Best ResponseYou've already chosen the best response.0is it just \[(t1)^4(t+5)^2\] ?

kobesaurus
 one year ago
Best ResponseYou've already chosen the best response.0with the chain rule those are not the derivatives...

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0yes but instead of 2 as an exponent its 3. i know im suppose to = 0 then im not sure what to do.

kobesaurus
 one year ago
Best ResponseYou've already chosen the best response.0wait that is right, t is single power, sorry.

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0okay so i did it wrong can we review step by step

kobesaurus
 one year ago
Best ResponseYou've already chosen the best response.0just to be clear, it isnt the two equations plus one another, its them two multiplied by one another?

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0so i get.... 4(t1)^3 3(t+5)^2

kobesaurus
 one year ago
Best ResponseYou've already chosen the best response.0(t1)^3 (t+5)^2 (17+7 t)

kobesaurus
 one year ago
Best ResponseYou've already chosen the best response.0I'm trying to figure that out, I used Wolframalpha to check my work and it got something different.

Azteck
 one year ago
Best ResponseYou've already chosen the best response.0Use the product rule!!! \[\huge s(t)= (t1)^4 (t+5)^3\] \[\huge s'(t)=4(t1)^3(t+5)^3+3(t+5)^2(t1)^4\] \[\huge =(t1)^3(t+5)^2[4t+20+3t3]\] \[\huge =(t1)^3(t+5)^2(7t+17)\] At S.P's s'(t)=0 \[\huge (t1)^3(t+5)^2(7t+17)=0\] \[\huge t=1, t=5, t=\frac{17}{7}\]

Azteck
 one year ago
Best ResponseYou've already chosen the best response.0\[s(t)=y\] To find the values of y, sub in the values of t into the original equation.

Azteck
 one year ago
Best ResponseYou've already chosen the best response.0Don't think you need to describe the nature of the curve [ie. Maximum or minimum turning point, etc.]. But I think you still need to find the inflection points of the function.

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0how did you get to this step: =(t−1)3(t+5)2[4t+20+3t−3]
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