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mathcalculusBest ResponseYou've already chosen the best response.0
i found the derivative. 4(t1)^3 3(t+5)^2
 one year ago

kobesaurusBest ResponseYou've already chosen the best response.0
is it just \[(t1)^4(t+5)^2\] ?
 one year ago

kobesaurusBest ResponseYou've already chosen the best response.0
with the chain rule those are not the derivatives...
 one year ago

mathcalculusBest ResponseYou've already chosen the best response.0
yes but instead of 2 as an exponent its 3. i know im suppose to = 0 then im not sure what to do.
 one year ago

kobesaurusBest ResponseYou've already chosen the best response.0
wait that is right, t is single power, sorry.
 one year ago

mathcalculusBest ResponseYou've already chosen the best response.0
okay so i did it wrong can we review step by step
 one year ago

kobesaurusBest ResponseYou've already chosen the best response.0
just to be clear, it isnt the two equations plus one another, its them two multiplied by one another?
 one year ago

mathcalculusBest ResponseYou've already chosen the best response.0
so i get.... 4(t1)^3 3(t+5)^2
 one year ago

kobesaurusBest ResponseYou've already chosen the best response.0
(t1)^3 (t+5)^2 (17+7 t)
 one year ago

kobesaurusBest ResponseYou've already chosen the best response.0
I'm trying to figure that out, I used Wolframalpha to check my work and it got something different.
 one year ago

AzteckBest ResponseYou've already chosen the best response.0
Use the product rule!!! \[\huge s(t)= (t1)^4 (t+5)^3\] \[\huge s'(t)=4(t1)^3(t+5)^3+3(t+5)^2(t1)^4\] \[\huge =(t1)^3(t+5)^2[4t+20+3t3]\] \[\huge =(t1)^3(t+5)^2(7t+17)\] At S.P's s'(t)=0 \[\huge (t1)^3(t+5)^2(7t+17)=0\] \[\huge t=1, t=5, t=\frac{17}{7}\]
 one year ago

AzteckBest ResponseYou've already chosen the best response.0
\[s(t)=y\] To find the values of y, sub in the values of t into the original equation.
 one year ago

AzteckBest ResponseYou've already chosen the best response.0
Don't think you need to describe the nature of the curve [ie. Maximum or minimum turning point, etc.]. But I think you still need to find the inflection points of the function.
 one year ago

mathcalculusBest ResponseYou've already chosen the best response.0
how did you get to this step: =(t−1)3(t+5)2[4t+20+3t−3]
 one year ago
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