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MarcLeclair
 2 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{a}^{b} e ^{2x}/(1+e^{x}) dx\] > its just an indefinite integral

MarcLeclair
 2 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{0}^{1} xln \left 1 + x ^{2} \right\]

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2u=1+e^x du = e^x dx e^{2x} = e^x *e^x where e^x = u1

MarcLeclair
 2 years ago
Best ResponseYou've already chosen the best response.0yea im stuck at u1/ u du

MarcLeclair
 2 years ago
Best ResponseYou've already chosen the best response.0oh so i can integrate u/u  1/u x.x

MarcLeclair
 2 years ago
Best ResponseYou've already chosen the best response.0Sorry the x.x isn't part of it

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2for 2nd, you'll just need to integrate ln u

MarcLeclair
 2 years ago
Best ResponseYou've already chosen the best response.0I thought I needed to use integration by part for expressions that had the product rule :/

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2when you can substitute and simplify, why go for parts ? :)

MarcLeclair
 2 years ago
Best ResponseYou've already chosen the best response.0oooohh and u= 1+ x^2 and du= 2xdx and du/2 = xdx. that was helpful :D

MarcLeclair
 2 years ago
Best ResponseYou've already chosen the best response.0so you don't always have to use integration by part when using something that includes the product rule? ( I'm referring to things like xe^x

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2still you'll need integration by parts to integrate ln u

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2not necessary always, forst try substitution

MarcLeclair
 2 years ago
Best ResponseYou've already chosen the best response.0ah so I have to change the limits of integration then go the integration by part. ALright thanks a lot!!

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2thats correct :) welcome ^_^
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