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MarcLeclairBest ResponseYou've already chosen the best response.0
\[\int\limits_{a}^{b} e ^{2x}/(1+e^{x}) dx\] > its just an indefinite integral
 one year ago

MarcLeclairBest ResponseYou've already chosen the best response.0
\[\int\limits_{0}^{1} xln \left 1 + x ^{2} \right\]
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
u=1+e^x du = e^x dx e^{2x} = e^x *e^x where e^x = u1
 one year ago

MarcLeclairBest ResponseYou've already chosen the best response.0
yea im stuck at u1/ u du
 one year ago

MarcLeclairBest ResponseYou've already chosen the best response.0
oh so i can integrate u/u  1/u x.x
 one year ago

MarcLeclairBest ResponseYou've already chosen the best response.0
Sorry the x.x isn't part of it
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
for 2nd, you'll just need to integrate ln u
 one year ago

MarcLeclairBest ResponseYou've already chosen the best response.0
I thought I needed to use integration by part for expressions that had the product rule :/
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
when you can substitute and simplify, why go for parts ? :)
 one year ago

MarcLeclairBest ResponseYou've already chosen the best response.0
oooohh and u= 1+ x^2 and du= 2xdx and du/2 = xdx. that was helpful :D
 one year ago

MarcLeclairBest ResponseYou've already chosen the best response.0
so you don't always have to use integration by part when using something that includes the product rule? ( I'm referring to things like xe^x
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
still you'll need integration by parts to integrate ln u
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
not necessary always, forst try substitution
 one year ago

MarcLeclairBest ResponseYou've already chosen the best response.0
ah so I have to change the limits of integration then go the integration by part. ALright thanks a lot!!
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
thats correct :) welcome ^_^
 one year ago
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