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MarcLeclair
 one year ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{a}^{b} e ^{2x}/(1+e^{x}) dx\] > its just an indefinite integral

MarcLeclair
 one year ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{0}^{1} xln \left 1 + x ^{2} \right\]

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2u=1+e^x du = e^x dx e^{2x} = e^x *e^x where e^x = u1

MarcLeclair
 one year ago
Best ResponseYou've already chosen the best response.0yea im stuck at u1/ u du

MarcLeclair
 one year ago
Best ResponseYou've already chosen the best response.0oh so i can integrate u/u  1/u x.x

MarcLeclair
 one year ago
Best ResponseYou've already chosen the best response.0Sorry the x.x isn't part of it

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2for 2nd, you'll just need to integrate ln u

MarcLeclair
 one year ago
Best ResponseYou've already chosen the best response.0I thought I needed to use integration by part for expressions that had the product rule :/

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2when you can substitute and simplify, why go for parts ? :)

MarcLeclair
 one year ago
Best ResponseYou've already chosen the best response.0oooohh and u= 1+ x^2 and du= 2xdx and du/2 = xdx. that was helpful :D

MarcLeclair
 one year ago
Best ResponseYou've already chosen the best response.0so you don't always have to use integration by part when using something that includes the product rule? ( I'm referring to things like xe^x

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2still you'll need integration by parts to integrate ln u

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2not necessary always, forst try substitution

MarcLeclair
 one year ago
Best ResponseYou've already chosen the best response.0ah so I have to change the limits of integration then go the integration by part. ALright thanks a lot!!

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2thats correct :) welcome ^_^
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