A variable X follows a normal distribution with mean 10 and standard deviation 5.
Another variable Y follows a normal distribution with mean 25 and standard deviation
10. The maximum height of the density curve for X is_______ (i) the maximum height for the density curve for Y , and the area under the density curve for
X is__________ (ii) the area under the density curve for Y .
(A) (i) greater than, (ii) less than
(B) (i) less than, (ii) greater than
(C) (i) equal to, (ii) equal to
(D) (i) greater than, (ii) equal to
(E) (i) less than, (ii) less than

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- anonymous

- schrodinger

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- UnkleRhaukus

there is something missing from your question

- anonymous

no its the actual question

- anonymous

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- anonymous

check that one

- anonymous

are u there?

- UnkleRhaukus

you have to compair the standard deviations of each curve, remember that the sum of areas under each curve is one

- anonymous

but , how ? could you explain it?

- UnkleRhaukus

|dw:1363240984062:dw|

- UnkleRhaukus

theses are two normal curves with the same mean , but different std.div

- UnkleRhaukus

the both have the same area ,; the sum of densities is one

- anonymous

there are not same mean?

- UnkleRhaukus

can you tell be which curve has the greatest std. div , the red or black curve

- anonymous

red?

- UnkleRhaukus

right , because less of the red is as close the mean as the black

- UnkleRhaukus

now if the means are different will this effect which is taller ?

- anonymous

no

- UnkleRhaukus

right , the maximun height of the curve is only dependent of the std.div

- UnkleRhaukus

So Y has a std.div of 10
and X has a std.div of 5

- UnkleRhaukus

something like this |dw:1363241494740:dw|

- anonymous

so x has higher density curve ?

- anonymous

and the area under the density curve for
X is less then (ii) the area under the density curve for Y .

- anonymous

is that righ?

- anonymous

hello?

- UnkleRhaukus

x has higher density ✓

- UnkleRhaukus

remember that the area under each density curve must sum to one

- anonymous

so its same

- anonymous

euqal

- UnkleRhaukus

yerh

- anonymous

thank you so much

- anonymous

i got it

- UnkleRhaukus

does it make senses now?

- anonymous

yes thanks

- UnkleRhaukus

cool

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