anonymous
  • anonymous
somebody please help me..got test tonight but still dunn how to solve this... The base of a triangle increases at the rate 2cm per second, and height decreases at the rate of 1/2cm per second.Find the rate of change f its area when the base and height are of length 5cm... ? T.T helpp
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
anybody ??? :(
anonymous
  • anonymous
you know agent00smith ?
agent0smith
  • agent0smith
hmm.... we know \[A = 0.5 b h\] \[\frac{ db }{ dt } = 2 (cm/s)\] \[\frac{ dh }{ dt }= -0.5 (cm/s)\] We need \[\frac{ dA }{ dt } = ?\]

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More answers

anonymous
  • anonymous
chain rule ?
anonymous
  • anonymous
but we have t differentiate A with respect to ??
agent0smith
  • agent0smith
Yeah that's what i'm trying to think of...
anonymous
  • anonymous
o.O ok ... i really dunno how to relate that
zepdrix
  • zepdrix
Hmm are we assuming this is a `right` triangle? :o
zepdrix
  • zepdrix
I guess it would have to be, otherwise we need more information. :) Looks like agent was on the right track. Both \(\large b\) and \(\large h\) are variables. Just apply the product rule! :D
zepdrix
  • zepdrix
Differentiate with respect to time*
agent0smith
  • agent0smith
Yeah that's what I was thinking... differentiate A wrt t
anonymous
  • anonymous
huh ??? yeahh differentiate wrt time . that is wwhat we want to find
anonymous
  • anonymous
im not clear with that
agent0smith
  • agent0smith
But then that seems to make the actual values of the base and height unnecessary, but maybe that's okay.... \[\frac{ dA }{ dt} = 0.5 \frac{ db }{ dt}\frac{ dh }{ dt}\]
zepdrix
  • zepdrix
Woops, product rule! :O
zepdrix
  • zepdrix
\[\large A=\frac{1}{2}bh\]\[\large A'=\frac{1}{2}b'h+\frac{1}{2}bh'\]Something like that, yes? :D
anonymous
  • anonymous
huhh ????? how can...i dont undrstand...
anonymous
  • anonymous
urmmm let me try that
anonymous
  • anonymous
wow.....yeahh!!! correct answer !!! greatt !! thank you so much guys ! love uollsz!! :D
zepdrix
  • zepdrix
yay team \:D/
anonymous
  • anonymous
my mentors :)
agent0smith
  • agent0smith
ah yes, my bad

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