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somebody please help me..got test tonight but still dunn how to solve this... The base of a triangle increases at the rate 2cm per second, and height decreases at the rate of 1/2cm per second.Find the rate of change f its area when the base and height are of length 5cm... ? T.T helpp

Mathematics
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anybody ??? :(
you know agent00smith ?
hmm.... we know \[A = 0.5 b h\] \[\frac{ db }{ dt } = 2 (cm/s)\] \[\frac{ dh }{ dt }= -0.5 (cm/s)\] We need \[\frac{ dA }{ dt } = ?\]

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Other answers:

chain rule ?
but we have t differentiate A with respect to ??
Yeah that's what i'm trying to think of...
o.O ok ... i really dunno how to relate that
Hmm are we assuming this is a `right` triangle? :o
I guess it would have to be, otherwise we need more information. :) Looks like agent was on the right track. Both \(\large b\) and \(\large h\) are variables. Just apply the product rule! :D
Differentiate with respect to time*
Yeah that's what I was thinking... differentiate A wrt t
huh ??? yeahh differentiate wrt time . that is wwhat we want to find
im not clear with that
But then that seems to make the actual values of the base and height unnecessary, but maybe that's okay.... \[\frac{ dA }{ dt} = 0.5 \frac{ db }{ dt}\frac{ dh }{ dt}\]
Woops, product rule! :O
\[\large A=\frac{1}{2}bh\]\[\large A'=\frac{1}{2}b'h+\frac{1}{2}bh'\]Something like that, yes? :D
huhh ????? how can...i dont undrstand...
urmmm let me try that
wow.....yeahh!!! correct answer !!! greatt !! thank you so much guys ! love uollsz!! :D
yay team \:D/
my mentors :)
ah yes, my bad

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