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Ika_Kim
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somebody please help me..got test tonight but still dunn how to solve this...
The base of a triangle increases at the rate 2cm per second, and height decreases at the rate of 1/2cm per second.Find the rate of change f its area when the base and height are of length 5cm... ? T.T helpp
 one year ago
 one year ago
Ika_Kim Group Title
somebody please help me..got test tonight but still dunn how to solve this... The base of a triangle increases at the rate 2cm per second, and height decreases at the rate of 1/2cm per second.Find the rate of change f its area when the base and height are of length 5cm... ? T.T helpp
 one year ago
 one year ago

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Ika_Kim Group TitleBest ResponseYou've already chosen the best response.0
anybody ??? :(
 one year ago

Ika_Kim Group TitleBest ResponseYou've already chosen the best response.0
you know agent00smith ?
 one year ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.0
hmm.... we know \[A = 0.5 b h\] \[\frac{ db }{ dt } = 2 (cm/s)\] \[\frac{ dh }{ dt }= 0.5 (cm/s)\] We need \[\frac{ dA }{ dt } = ?\]
 one year ago

Ika_Kim Group TitleBest ResponseYou've already chosen the best response.0
chain rule ?
 one year ago

Ika_Kim Group TitleBest ResponseYou've already chosen the best response.0
but we have t differentiate A with respect to ??
 one year ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.0
Yeah that's what i'm trying to think of...
 one year ago

Ika_Kim Group TitleBest ResponseYou've already chosen the best response.0
o.O ok ... i really dunno how to relate that
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Hmm are we assuming this is a `right` triangle? :o
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
I guess it would have to be, otherwise we need more information. :) Looks like agent was on the right track. Both \(\large b\) and \(\large h\) are variables. Just apply the product rule! :D
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Differentiate with respect to time*
 one year ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.0
Yeah that's what I was thinking... differentiate A wrt t
 one year ago

Ika_Kim Group TitleBest ResponseYou've already chosen the best response.0
huh ??? yeahh differentiate wrt time . that is wwhat we want to find
 one year ago

Ika_Kim Group TitleBest ResponseYou've already chosen the best response.0
im not clear with that
 one year ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.0
But then that seems to make the actual values of the base and height unnecessary, but maybe that's okay.... \[\frac{ dA }{ dt} = 0.5 \frac{ db }{ dt}\frac{ dh }{ dt}\]
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Woops, product rule! :O
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
\[\large A=\frac{1}{2}bh\]\[\large A'=\frac{1}{2}b'h+\frac{1}{2}bh'\]Something like that, yes? :D
 one year ago

Ika_Kim Group TitleBest ResponseYou've already chosen the best response.0
huhh ????? how can...i dont undrstand...
 one year ago

Ika_Kim Group TitleBest ResponseYou've already chosen the best response.0
urmmm let me try that
 one year ago

Ika_Kim Group TitleBest ResponseYou've already chosen the best response.0
wow.....yeahh!!! correct answer !!! greatt !! thank you so much guys ! love uollsz!! :D
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
yay team \:D/
 one year ago

Ika_Kim Group TitleBest ResponseYou've already chosen the best response.0
my mentors :)
 one year ago

agent0smith Group TitleBest ResponseYou've already chosen the best response.0
ah yes, my bad
 one year ago
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