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Ika_Kim

  • 3 years ago

somebody please help me..got test tonight but still dunn how to solve this... The base of a triangle increases at the rate 2cm per second, and height decreases at the rate of 1/2cm per second.Find the rate of change f its area when the base and height are of length 5cm... ? T.T helpp

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  1. Ika_Kim
    • 3 years ago
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    anybody ??? :(

  2. Ika_Kim
    • 3 years ago
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    you know agent00smith ?

  3. agent0smith
    • 3 years ago
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    hmm.... we know \[A = 0.5 b h\] \[\frac{ db }{ dt } = 2 (cm/s)\] \[\frac{ dh }{ dt }= -0.5 (cm/s)\] We need \[\frac{ dA }{ dt } = ?\]

  4. Ika_Kim
    • 3 years ago
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    chain rule ?

  5. Ika_Kim
    • 3 years ago
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    but we have t differentiate A with respect to ??

  6. agent0smith
    • 3 years ago
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    Yeah that's what i'm trying to think of...

  7. Ika_Kim
    • 3 years ago
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    o.O ok ... i really dunno how to relate that

  8. zepdrix
    • 3 years ago
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    Hmm are we assuming this is a `right` triangle? :o

  9. zepdrix
    • 3 years ago
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    I guess it would have to be, otherwise we need more information. :) Looks like agent was on the right track. Both \(\large b\) and \(\large h\) are variables. Just apply the product rule! :D

  10. zepdrix
    • 3 years ago
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    Differentiate with respect to time*

  11. agent0smith
    • 3 years ago
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    Yeah that's what I was thinking... differentiate A wrt t

  12. Ika_Kim
    • 3 years ago
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    huh ??? yeahh differentiate wrt time . that is wwhat we want to find

  13. Ika_Kim
    • 3 years ago
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    im not clear with that

  14. agent0smith
    • 3 years ago
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    But then that seems to make the actual values of the base and height unnecessary, but maybe that's okay.... \[\frac{ dA }{ dt} = 0.5 \frac{ db }{ dt}\frac{ dh }{ dt}\]

  15. zepdrix
    • 3 years ago
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    Woops, product rule! :O

  16. zepdrix
    • 3 years ago
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    \[\large A=\frac{1}{2}bh\]\[\large A'=\frac{1}{2}b'h+\frac{1}{2}bh'\]Something like that, yes? :D

  17. Ika_Kim
    • 3 years ago
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    huhh ????? how can...i dont undrstand...

  18. Ika_Kim
    • 3 years ago
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    urmmm let me try that

  19. Ika_Kim
    • 3 years ago
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    wow.....yeahh!!! correct answer !!! greatt !! thank you so much guys ! love uollsz!! :D

  20. zepdrix
    • 3 years ago
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    yay team \:D/

  21. Ika_Kim
    • 3 years ago
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    my mentors :)

  22. agent0smith
    • 3 years ago
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    ah yes, my bad

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