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anonymous
 3 years ago
somebody please help me..got test tonight but still dunn how to solve this...
The base of a triangle increases at the rate 2cm per second, and height decreases at the rate of 1/2cm per second.Find the rate of change f its area when the base and height are of length 5cm... ? T.T helpp
anonymous
 3 years ago
somebody please help me..got test tonight but still dunn how to solve this... The base of a triangle increases at the rate 2cm per second, and height decreases at the rate of 1/2cm per second.Find the rate of change f its area when the base and height are of length 5cm... ? T.T helpp

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you know agent00smith ?

agent0smith
 3 years ago
Best ResponseYou've already chosen the best response.0hmm.... we know \[A = 0.5 b h\] \[\frac{ db }{ dt } = 2 (cm/s)\] \[\frac{ dh }{ dt }= 0.5 (cm/s)\] We need \[\frac{ dA }{ dt } = ?\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but we have t differentiate A with respect to ??

agent0smith
 3 years ago
Best ResponseYou've already chosen the best response.0Yeah that's what i'm trying to think of...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0o.O ok ... i really dunno how to relate that

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1Hmm are we assuming this is a `right` triangle? :o

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1I guess it would have to be, otherwise we need more information. :) Looks like agent was on the right track. Both \(\large b\) and \(\large h\) are variables. Just apply the product rule! :D

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1Differentiate with respect to time*

agent0smith
 3 years ago
Best ResponseYou've already chosen the best response.0Yeah that's what I was thinking... differentiate A wrt t

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0huh ??? yeahh differentiate wrt time . that is wwhat we want to find

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0im not clear with that

agent0smith
 3 years ago
Best ResponseYou've already chosen the best response.0But then that seems to make the actual values of the base and height unnecessary, but maybe that's okay.... \[\frac{ dA }{ dt} = 0.5 \frac{ db }{ dt}\frac{ dh }{ dt}\]

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1Woops, product rule! :O

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1\[\large A=\frac{1}{2}bh\]\[\large A'=\frac{1}{2}b'h+\frac{1}{2}bh'\]Something like that, yes? :D

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0huhh ????? how can...i dont undrstand...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0urmmm let me try that

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0wow.....yeahh!!! correct answer !!! greatt !! thank you so much guys ! love uollsz!! :D
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