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I probably have the correct number of favorable outcomes for this, but can anyone tell me what should be the sample space ?
 one year ago
 one year ago
I probably have the correct number of favorable outcomes for this, but can anyone tell me what should be the sample space ?
 one year ago
 one year ago

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shubhamsrgBest ResponseYou've already chosen the best response.0
http://gyazo.com/7df2a488ddba6e26108b9830d264fa5b
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
fav no. of outcomes =4096, I ran a c++ program for that, in case anyone would like to view it ?
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
am not too sure with the sample space.
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
i am not sure but one version of the sample space is just all possible \(6^6\) outcomes when you roll six dice
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
yep that was my first attempt, which leads us to 64/729 i.e. ans = 793 , but it tells me the ans is wrong. Sample space should be something else, as we are allowed to arrange.
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
well not really, the sample space is usually defined to be "the set of all possible outcomes" but not necessarily the denominator of your probability
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
the fact that you cannot distinguish between (a,b,c,d,e,f) from (a,d,b,e,c,f) does not make them the same outcome
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
but should shut up because i have read your problem now 6 or 7 times and i do not understand it. it seems like the probability would depend on k
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
oh geez, yes i do! seems very very complicated
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
i would have no idea how to do this
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
hmm please tell me if I am understanding the problem correctly myself : we throw 6 dice 1st no. should not be div by 3 sum of 1st 2 should also not be div by 3 sum of 1st 3.. . . 6
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
evidently you have to exclude any 3 and any 6, but after that i cannot imagine how you proceed
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
yeah what you said is what i think it is
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
so for example the ordering on the left in the example does not work, but the ordering on the right does, so that one would be considered a success
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
Hint: Let x be sum of outcomes of all 6 die then, Look for case x Mod 3=1 And case x Mod 3 = 2 only..... This will simplify the problem
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
I never really followed :/
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
Should I post the whole solution?
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
Actually I found a solution on yahooanswers, didn't follow that either :P
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
wait, I shall post the link ^_^
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
http://answers.yahoo.com/question/index?qid=20130312081947AAUNJ7K
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
when x Mod 3=1 then, out of the six numbers, u can pick 3 numbers such that their sum is "a" where "a "mod 3 =0 and the rest three numbers sum is b where b mod 3=1
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
Now, Let p=1Mod3=4Mod3=1 , q=2Mod3=5Mod3=2 , r=3Mod3=6Mod6=0 So, to pick three numbers such their sum is divisible by 3, r,r,r r,p,q p,p,p q,q,q to pick three numbers such that their is b where b mod 3=1, r,r,p r,q,q p,p,q
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
So, x mod 3=1 only when, r,r,r,r,r,p r,r,r,r,q,q r,r,r,p,p,q r,p,q,r,r,p r,p,q,r,q,q r,p,q,p,p,q p,p,p,r,r,p p,p,p,r,q,q p,p,p,p,p,q q,q,q,r,r,p q,q,q,r,q,q q,q,q,p,p,q
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
Since, r=0, p =1,q=2 r,r,r,r,r,p = 0,0,0,0,0,1 r,r,r,r,q,q=0,0,0,0,2,2 r,r,r,p,p,q=0,0,0,1,1,2 r,p,q,r,r,p=0,0,0,1,1,2 >This is repeated r,p,q,r,q,q=0,0,1,2,2,2 r,p,q,p,p,q=0,1,1,1,2,2 p,p,p,r,r,p=0,0,1,1,1,1 p,p,p,r,q,q=0,1,1,1,2,2>This is repeated p,p,p,p,p,q=1,1,1,1,1,2 q,q,q,r,r,p=0,0,1,2,2,2 >This is repeated q,q,q,r,q,q=0,2,2,2,2,2 q,q,q,p,p,q=1,1,2,2,2,2
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
Now, out of these , r,r,r,r,r,p = 0,0,0,0,0,1 r,r,r,r,q,q=0,0,0,0,2,2 r,r,r,p,p,q=0,0,0,1,1,2 r,p,q,r,q,q=0,0,1,2,2,2 r,p,q,p,p,q=0,1,1,1,2,2 p,p,p,r,r,p=0,0,1,1,1,1 p,p,p,p,p,q=1,1,1,1,1,2 q,q,q,r,q,q=0,2,2,2,2,2 q,q,q,p,p,q=1,1,2,2,2,2 which can u arrange such that the sum of the first k numbers is not divisible by 3.
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
Please give me some time to grasp.
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
Am so sorry could not understand, my head aches! :( I'll give it a fresh start later : so sorry :/
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
Thanks a ton sire! I was revising this and everything is crystal clear now! ^_^ Can't thank you enough..
 one year ago
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