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Ummmm..
Just Curious..
But what does a triple and quadruple differenciation of a function signify graphically??
I know its increasing or decreasing with first derivative, second tells concavity that means how much..
But whats the role of 3rd and 4th???
 one year ago
 one year ago
Ummmm.. Just Curious.. But what does a triple and quadruple differenciation of a function signify graphically?? I know its increasing or decreasing with first derivative, second tells concavity that means how much.. But whats the role of 3rd and 4th???
 one year ago
 one year ago

This Question is Closed

amistre64Best ResponseYou've already chosen the best response.3
f''' is acceleration, and f'''' is called a jerk; the speed at which the acceleration is changing
 one year ago

amistre64Best ResponseYou've already chosen the best response.3
all the derivatives combined tell us how a function is moving at a single point
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
\(f'''\) is a jerk? I think I am the \(f'''\) you are looking for :)
 one year ago

amistre64Best ResponseYou've already chosen the best response.3
spose you wanted to create a polynomial that moved like the sine function both functions would have to MOVE in the same manner, and all of their derivaties would have to be equal
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
I don't wanna know it what it means in terms of distance travelled.. Just in general term..
 one year ago

terenzreignzBest ResponseYou've already chosen the best response.2
hey @amistre64 I think it's the third derivative that's the jerk?
 one year ago

amistre64Best ResponseYou've already chosen the best response.3
maybe, i lost count after 1.5
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
yah its the third derivative..
 one year ago

terenzreignzBest ResponseYou've already chosen the best response.2
LOL Unless f' is the position function and f is... some function whose derivative is the position function XD
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
Welllllllll... So can anybody answer my question?? Please??
 one year ago

terenzreignzBest ResponseYou've already chosen the best response.2
Well... f'(c) is the slope of the tangent line at the point x = c f''(c) is the concavity of the graph at the point x = c f'''(c) is the rate of change of the concavity??? XD
 one year ago

amistre64Best ResponseYou've already chosen the best response.3
"all the derivatives combined tell us how a function is moving at a single point" by, amistre64
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
@terenzreignz As much of a guess that was it actually is the right answer!! :D :P
 one year ago

TuringTestBest ResponseYou've already chosen the best response.0
concavity is the rate change of the slope, so all that is saying is the rate change of the rate change of the slope, which we can extend to all derivatives.
 one year ago

amistre64Best ResponseYou've already chosen the best response.3
sin(0) = 0 ; P(x) = 0 sin'(0) = 1 ; P(x) = 0 + x sin''(0) = 0 ; P(x) = 0 + x +0x^2/2! sin'''(0) = 1 ; P(x) = 0 + x +0x^2/2! x^3/3! sin(x) = P(x)= \(\Large\sum_{n=0}^{\inf}\frac{(1)^n}{(2n+1)!}x^{2n+1}\)
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
That just prove sine function is an oscillating function.. nonetheless thank you to all!! :P
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
@amistre64 Though if I missed something in your post, Do point out..
 one year ago

amistre64Best ResponseYou've already chosen the best response.3
i was just demonstrating that the successive derivatives of a function define how it is moving at a single point, and that 2 function that are equal at a single point, and equal at all their successive derivatives are the same at that point. Since polynomials are so much easier to play with, if we can construct a polynomial to work from, that converges (is the same), at a point or range of points. Then mathing is so much simpler
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
:D A very good point Indeed!!
 one year ago
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