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anonymous
 3 years ago
Ummmm..
Just Curious..
But what does a triple and quadruple differenciation of a function signify graphically??
I know its increasing or decreasing with first derivative, second tells concavity that means how much..
But whats the role of 3rd and 4th???
anonymous
 3 years ago
Ummmm.. Just Curious.. But what does a triple and quadruple differenciation of a function signify graphically?? I know its increasing or decreasing with first derivative, second tells concavity that means how much.. But whats the role of 3rd and 4th???

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amistre64
 3 years ago
Best ResponseYou've already chosen the best response.3f''' is acceleration, and f'''' is called a jerk; the speed at which the acceleration is changing

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.3all the derivatives combined tell us how a function is moving at a single point

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.0\(f'''\) is a jerk? I think I am the \(f'''\) you are looking for :)

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.3spose you wanted to create a polynomial that moved like the sine function both functions would have to MOVE in the same manner, and all of their derivaties would have to be equal

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I don't wanna know it what it means in terms of distance travelled.. Just in general term..

terenzreignz
 3 years ago
Best ResponseYou've already chosen the best response.2hey @amistre64 I think it's the third derivative that's the jerk?

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.3maybe, i lost count after 1.5

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yah its the third derivative..

terenzreignz
 3 years ago
Best ResponseYou've already chosen the best response.2LOL Unless f' is the position function and f is... some function whose derivative is the position function XD

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Welllllllll... So can anybody answer my question?? Please??

terenzreignz
 3 years ago
Best ResponseYou've already chosen the best response.2Well... f'(c) is the slope of the tangent line at the point x = c f''(c) is the concavity of the graph at the point x = c f'''(c) is the rate of change of the concavity??? XD

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.3"all the derivatives combined tell us how a function is moving at a single point" by, amistre64

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@terenzreignz As much of a guess that was it actually is the right answer!! :D :P

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.0concavity is the rate change of the slope, so all that is saying is the rate change of the rate change of the slope, which we can extend to all derivatives.

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.3sin(0) = 0 ; P(x) = 0 sin'(0) = 1 ; P(x) = 0 + x sin''(0) = 0 ; P(x) = 0 + x +0x^2/2! sin'''(0) = 1 ; P(x) = 0 + x +0x^2/2! x^3/3! sin(x) = P(x)= \(\Large\sum_{n=0}^{\inf}\frac{(1)^n}{(2n+1)!}x^{2n+1}\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0That just prove sine function is an oscillating function.. nonetheless thank you to all!! :P

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@amistre64 Though if I missed something in your post, Do point out..

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.3i was just demonstrating that the successive derivatives of a function define how it is moving at a single point, and that 2 function that are equal at a single point, and equal at all their successive derivatives are the same at that point. Since polynomials are so much easier to play with, if we can construct a polynomial to work from, that converges (is the same), at a point or range of points. Then mathing is so much simpler

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0:D A very good point Indeed!!
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