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mathcalculus
Group Title
helpppp: find the critical points: s(t)= (t1)^4 (t+5)^3
 one year ago
 one year ago
mathcalculus Group Title
helpppp: find the critical points: s(t)= (t1)^4 (t+5)^3
 one year ago
 one year ago

This Question is Closed

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
@mathcalculus , what have you tried?
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
yes, i used the product rule: \[\frac{ d }{ dx } (t1)^{4}* (t+5)^{3}= (t1)^{4} * 3(t+5)^{2} + (t+5)^{3} * 4(t1)^{3}\]
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
then from there, i'm stuck.
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
ok, so far so good. Now, factor out the greatest common factor of both terms. For example, they both have a factor of (t1)^3, but that's not all they have in common. What else?
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
Don't they both have a factor of t+5 to a power?
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
oh yes, but are from opposite sides..
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
doesn't matter the order. AB+CA=A(B+C)
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
can you explain to me. i dont really see where we are going with factoring
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
The purpose in factoring is to simplify the derivative into a product of three factors. One of the factors will be t1 to a power, a second factor will be t+5 to a power, and then you will be left with some factor containing a t as well.
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
And then once you have your derivative in factored form, you can set each factor equal to zero to find your critical points.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
can you show me
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
i understand what youre saying but not how sure how to do that.
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
Ok, lets look at the t1 term in each expression.
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
What is the largest exponent they share?
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
now i know that i write (t1)^3
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
but what happens to the 4?
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
Exactly, so, we may factor out a \[\left( t1 \right)^{3}\] from both expressions. Hang on, we will come to that.
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
Let's take a looke at the first expression in its entirety. If all you are removing is the \[\left( t1 \right)^{3}\] You would be left with \[4\left( t+5 \right)^{3}\]
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
Do you see that?
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
no if i was to see the common factor.. i would get (t1)^3+ (t+5)^2.... then what do i do with the numbers that are left...?
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
ok,, there is your mistake. It isn't a sum. It's a product.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
ok so i dont see how you got 4(t+5)^3
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
Hang on, I was only talking about factoring out the t1 from the first expression,, not from the whole thing.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
well you showed me that
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
Hang on my pc is giving me fits.
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
dw:1363286087022:dw
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
why 4(t+5)?????
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
On the outside is what they both have in common, on ther inside is what is left after you have factored out that common factor.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
i understand this part... (t1)^3* (t+5)^2
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
Rememmber when I was saying if all we factored out was the (t1)^2 You would have the 4(t+5)^3 left.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
but then i dont understand why it is 4(t+5) ... i did this..4(t1) + 3(t+5)
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
Well, now we include a (t+5)^2 as well, so what is left from the 4(t+5)^3? Just the 4(t+5).
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
i understand...
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
im left with 7t+17
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
t= 17/7
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
Perfect. So, now that each expression of the derivative is writtern in factored form, we set each of them equal to zero to find your critical points.
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
That is one of your critical points. There are two others.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
ok so (t1)^3 = 0
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
x= 0?
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
Not quite.
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
If (t1)^3=0 then t=1
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
Now you have one more to do.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
1? how?
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
Tinme for lunch, I will come back shortly to see if you have finished it.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
the exponent is in the way.
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
Well, raise each side to the 1/3 power. That will get rid of your exponent.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
kkk but how do we find the y
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
Just go back in and substitute the critical values.
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
For t=1 and t=5, you will get y=0. But for t=17/7, you won't get y=0.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
i did....
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
(11)^4 (1+5)^3
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
and 17/7 i got a huge number.. doesn;t make sense.. :(
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
i got 432/823543
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
Well, you will need to raise some fractions with a denominator of 7 to the 4th and 3rd powers, so yeah, it will get rather ugly!
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
i see that but it keeps saying the critical points are wrong.
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
ok, I need to see the original problem. And what keeps saying your critical points are wrong?
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
Are you using an online program?
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
webwork.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
i attached it.
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
Your value for t=17/7 is incorrect
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
You should get a large numerator divided by a denominator of 7^7.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
so i dont know where i went wrong...
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
The numerator should be (24)^4(18)^3
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
we did this step by step... now t is wrong?? really?
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
No, t is not wrong, but your evaluation of the function for t=17/7 is incorrect.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
so now how do i solve that?
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
obviously i know its wrong.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
ive tried this problem out 3294810347 times.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
now what do i do?
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
Should have (17/71)^4(17/7+5)^3
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
huhhh???
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ 17 }{ 7 }1=\frac{ 24 }{ 7 }\] and \[\frac{ 17 }{ 7 }+5=\frac{ 18 }{ 7 }\]
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
wow this is insane. ive spent an hour to 2 with this problem.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
why?? why did we ignore the exponents???
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
Now raise each of those terms to the appropriate powers.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
sn;t it suppose to be part of it?? the original problem we were given??
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
i did
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
we didn't I was just showing you step by step.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
thats how i got the hugeeeeeeee number
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
and so did i. i had it on paper.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
what i dont understand is that youre basically saying raise those to the power.. in other words, im redoing this whole crap again.
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
Well, the numerator should be larger than your denominator, and it wasn't according to your answer.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
which AGAIN, is leading m to the wrong huge answer i had before
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
No, you are finding the yvalue that goes with the value you ccame out for t.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
so there are 4 crtical points now?
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
or 3??
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
youre saying raise hem to the power and multiple right???
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
do you know rasing them to the power is going to GIVE ME A HUGEEEEEE NUMBER??
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
do you not see that was what i had in the first place??
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
There are only the three values of t we came up with, but you want them as ordered pairs, yo
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
ok good3 values done.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
obviously i want them in order pairs.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
i did EXACTLY what you just did with the 17/7 and got those numbers.
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
I see that, but your answer for t=17/7 showed a smaller numerator than denominator and it shouldd be the other way around.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
then show me.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
whats the y value for 17/7
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
How did you do that? Each numerator is larger than each denominator and they both have total of 7th powers.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
ok find the answer.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
i need to see if it's correct
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
i cant keep wasting 23 hours on one problem.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
@calcmat, are you stuck?
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
\[\left( \frac{ 24 }{ 7 } \right)^{4}\times \left( \frac{ 18 }{ 7} \right)\]
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
now 18/7 needs to be raised to the 3rd power.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
ACCORDING TO THE ORIGINAL PROBLEM
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
Should gha have a 3 on the second expression for the power.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
and i just proved my point. you are taking em to the wrong direction AGAIN.
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
What are you talking about.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
I ASKED YOU ONE SIMPLE QUESTION. CAN YOU FIND THE ANSWER?
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
I WANT TO SEE IF WHAT YOU'RE DOING IS ACTUALLY CORRECT
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
IVE SPENT 23 HOURS WITH YOU IN THIS PROBLEM.
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
Hey, don't get mad at me, I am the one spending MY TIME helping YOU.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
YOURE STILL NOT ANSWERING MY QUESTION.
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
You can answer the question by taking (24/7)^4(18/7)^3
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
I DID. STILL A HUGE NUMBER
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
I got 2349.5 rounded to 1 decimal place.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
WRONG BUDDY.
 one year ago

dan815 Group TitleBest ResponseYou've already chosen the best response.0
(1+t)^3 (5+t)^2 (17+7 t) your 0's = 1,5,17/7
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
nvm. i''ll solve it
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
thanks everyone.
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
Those are the ones I got @dan815
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
that part is correct.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
and @calmat01 don't round. thats wrong.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
keep the numbers just the way they are. p.s found the answer. thanks.
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
Ok, so my answer wasn't completely off?
 one year ago

dan815 Group TitleBest ResponseYou've already chosen the best response.0
mathcalculus can you prove the divergence theorem for me?
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
So you are telling me that you should have left the answer as 1934917632/823543? That's insane @mathcalculus
 one year ago

dan815 Group TitleBest ResponseYou've already chosen the best response.0
what are all these big numbers?
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
lol insane.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
your explanation was confusing. but the numbers are correct.
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
Gee, I spent all that time being patient with you, and all I get is my explanation was confusing?
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
lol truth to be told...truth be told.
 one year ago

calmat01 Group TitleBest ResponseYou've already chosen the best response.0
I see. Well, if truth be told, the reason it was confusing was because you forgot how to factor. But I am not bitter. Take care and good luck with the rest of your assignment.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
I did factor. I just didn't put it up because I was trying to understand you. And also, you were throwing out numbers without reason. & I'm glad you're not so bitter to take my words sensibly:) Thank you.
 one year ago
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