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anonymous
 3 years ago
help: find the critical points: g(x) x+8/x1
anonymous
 3 years ago
help: find the critical points: g(x) x+8/x1

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ d }{ dx} \frac{ x+8 }{ x1 }= \frac{ 1(x1) 1(x+8)}{(x1)(x1) }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 1x11x8 }{ x ^{2}2x+1 }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 9 }{ x ^{2} 2x+1 }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0then I'm stuck here :/

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Find x in: \[\frac{ 9 }{ x^22x+1 } = 0\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Remember that the value of the derivative is the slope of the line of g(x) at that point so when the first derivative is equal to zero, the slope of the curve is zero and it is therefore a critical point.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that's what I did later..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0No, when x = 0 then the function is equal to 9...find the value of x so that the dericative is equal to 0.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Also, since there is no solution for that equation (just realised :p) You can find at which point it is undefined.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes, i end up with 9=0 can you show me?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it's undefined right? because the x is not there..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0unless it was something like 9x/ x^22x+1

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0then there would be an x.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but since 9 is alone... there is no critical point. right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Correct, but there IS an asymptote in the graph so I'm not sure if you'd consider that a critical point in your class?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0how did you find 1 again?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Set the bottom of the function equal to zero so x^22x+1 = 0 and solve for x. No problem :D
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