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Do you know the derivative?

yes i did everything. x= 2/15 and x= 8

those are the critical points.

Okay you don't consider \(f(8)\) for the \([0,4]\) interval..

oh......

It's apparent that \(f(2/15)\) is the maximum.

And the minimum is going to be \(f(4)\)

just 2/15? or do we write that the max as: 4.06074

so the min has to be: -589

I said \(f(2/15)\) which is equal to \(4.06074\)

okay. then what's the minimum

Now you just need to check 9 and -9 for the other interval.

since i can't use f(8)

For the \([0,4]\) interval, the minimum is -589 right?

i think so...

after i do all the work, the problem is i don't know how to pick the min and max.

for f(-9)= -8727 and for f(9) = -1149.

Yeah... the minimum is the LOWEST value the maximum is the HIGHEST value.

You only have to consider the values at critical points and endpoints.

i submitted this as my answer but it says its wrong. :(

You must be doing it wrong then... somehow.

i know that's why im asking you if the answer i had up there are correct.

What's your derivative?

15x^2-122x+16