anonymous
  • anonymous
Integrate (e^2x)/(e^x-3) times dx
Calculus1
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
|dw:1363307046027:dw|
anonymous
  • anonymous
let us consider e^x = t => st = e^x dx
anonymous
  • anonymous
|dw:1363307129744:dw|

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
|dw:1363307205619:dw|
anonymous
  • anonymous
|dw:1363307271643:dw|
anonymous
  • anonymous
It's a simple \(u=e^x-3,\, du=e^xdx\) substitution.\[ \int \frac{e^{2x}}{e^x-3}dx = \int\frac{u+3}{u}du = \int 1 + \frac{3}{u}du \]
tkhunny
  • tkhunny
Note: It's not "times" dx. There is no multiplication, there.
anonymous
  • anonymous
Oh that's true. So which one of the answers is the correct way to solve then? Integration is a real struggle for me
tkhunny
  • tkhunny
Well, you are supposed to be learning. A bit of difficulty should not be construed as a bad sign. Put in the time and thought. Looks like wio and DHASHNI already did most of the work for you. You do the rest.

Looking for something else?

Not the answer you are looking for? Search for more explanations.