## grobles27 one year ago Integrate (e^2x)/(e^x-3) times dx

1. DHASHNI

|dw:1363307046027:dw|

2. DHASHNI

let us consider e^x = t => st = e^x dx

3. DHASHNI

|dw:1363307129744:dw|

4. DHASHNI

|dw:1363307205619:dw|

5. DHASHNI

|dw:1363307271643:dw|

6. wio

It's a simple $$u=e^x-3,\, du=e^xdx$$ substitution.$\int \frac{e^{2x}}{e^x-3}dx = \int\frac{u+3}{u}du = \int 1 + \frac{3}{u}du$

7. tkhunny

Note: It's not "times" dx. There is no multiplication, there.

8. grobles27

Oh that's true. So which one of the answers is the correct way to solve then? Integration is a real struggle for me

9. tkhunny

Well, you are supposed to be learning. A bit of difficulty should not be construed as a bad sign. Put in the time and thought. Looks like wio and DHASHNI already did most of the work for you. You do the rest.