grobles27
Integrate (e^2x)/(e^x-3) times dx
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DHASHNI
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|dw:1363307046027:dw|
DHASHNI
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let us consider e^x = t
=> st = e^x dx
DHASHNI
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DHASHNI
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DHASHNI
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wio
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It's a simple \(u=e^x-3,\, du=e^xdx\) substitution.\[
\int \frac{e^{2x}}{e^x-3}dx = \int\frac{u+3}{u}du = \int 1 + \frac{3}{u}du
\]
tkhunny
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Note: It's not "times" dx. There is no multiplication, there.
grobles27
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Oh that's true. So which one of the answers is the correct way to solve then? Integration is a real struggle for me
tkhunny
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Well, you are supposed to be learning. A bit of difficulty should not be construed as a bad sign. Put in the time and thought.
Looks like wio and DHASHNI already did most of the work for you. You do the rest.