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 one year ago
HELP so frustrating!! Determine the extrema of below on the given interval
f(x)=5x^361x^2+16x+3
(a) on [0,4]
The minimum is ?? and the maximum is ??
(b) on [9,9]
The minimum is ?? and the maximum is ??
please solve so i can know which answer i got wrong.
 one year ago
HELP so frustrating!! Determine the extrema of below on the given interval f(x)=5x^361x^2+16x+3 (a) on [0,4] The minimum is ?? and the maximum is ?? (b) on [9,9] The minimum is ?? and the maximum is ?? please solve so i can know which answer i got wrong.

This Question is Closed

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0can someone please tell me the correct answer to this. it seems like one of my answers is incorrect.

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1check \(f(0), f(4)\) and also find the critical point and find \(f\) of that number

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0a) on [0,4] The minimum is 589 and the maximum is 4.06074 (b) on [9,9] The minimum is 8727 and the maximum is 1149

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1the derivative is \( 15 x^2122 x+16\)

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1which, by some miracle factors as \((x8) (15 x2)\)

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1zeros of the derivative are \(\frac{2}{15}\) and \(8\)

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1so \(\frac{2}{15}\) is the \(x\) coordinate of the local max and \(8\) is the \(x\) coordinate of the local min

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0so for the intervals [0,4] max is: 2/15 and 8 is the min? what about [9,9]

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0i just want to make sure because it submitted the answer and it keeps saying its wrong.

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0any one! this is important!

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0never mind! i found it. thanks to those who actually helped.

Peter14
 one year ago
Best ResponseYou've already chosen the best response.0f'(x)=10x^2  122x +16 0=10x^2  122x + 16 (just working here because I don't have paper handy)

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1careful here the max is the \(y\) value not the \(x\) value

Peter14
 one year ago
Best ResponseYou've already chosen the best response.0just finding critical points

Peter14
 one year ago
Best ResponseYou've already chosen the best response.0oh, sorry you already found them

satellite73
 one year ago
Best ResponseYou've already chosen the best response.18 is not in the interval \([0,4]\) for that one, you need to check \(f(0), f(4), f(\frac{2}{15})\) the largest is the max and the smallest is the min

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1for \([9,9]\) you need to check \[f(9),f(\frac{2}{15}), f(8), f(9)\]

mathcalculus
 one year ago
Best ResponseYou've already chosen the best response.0got it. thank you!
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