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mathcalculus
Group Title
HELP so frustrating!! Determine the extrema of below on the given interval
f(x)=5x^361x^2+16x+3
(a) on [0,4]
The minimum is ?? and the maximum is ??
(b) on [9,9]
The minimum is ?? and the maximum is ??
please solve so i can know which answer i got wrong.
 one year ago
 one year ago
mathcalculus Group Title
HELP so frustrating!! Determine the extrema of below on the given interval f(x)=5x^361x^2+16x+3 (a) on [0,4] The minimum is ?? and the maximum is ?? (b) on [9,9] The minimum is ?? and the maximum is ?? please solve so i can know which answer i got wrong.
 one year ago
 one year ago

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mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
can someone please tell me the correct answer to this. it seems like one of my answers is incorrect.
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
check \(f(0), f(4)\) and also find the critical point and find \(f\) of that number
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
a) on [0,4] The minimum is 589 and the maximum is 4.06074 (b) on [9,9] The minimum is 8727 and the maximum is 1149
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
the derivative is \( 15 x^2122 x+16\)
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
which, by some miracle factors as \((x8) (15 x2)\)
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
zeros of the derivative are \(\frac{2}{15}\) and \(8\)
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
so \(\frac{2}{15}\) is the \(x\) coordinate of the local max and \(8\) is the \(x\) coordinate of the local min
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
so for the intervals [0,4] max is: 2/15 and 8 is the min? what about [9,9]
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
i just want to make sure because it submitted the answer and it keeps saying its wrong.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
@satellite73
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
any one! this is important!
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
never mind! i found it. thanks to those who actually helped.
 one year ago

Peter14 Group TitleBest ResponseYou've already chosen the best response.0
f'(x)=10x^2  122x +16 0=10x^2  122x + 16 (just working here because I don't have paper handy)
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
careful here the max is the \(y\) value not the \(x\) value
 one year ago

Peter14 Group TitleBest ResponseYou've already chosen the best response.0
just finding critical points
 one year ago

Peter14 Group TitleBest ResponseYou've already chosen the best response.0
oh, sorry you already found them
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
8 is not in the interval \([0,4]\) for that one, you need to check \(f(0), f(4), f(\frac{2}{15})\) the largest is the max and the smallest is the min
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
for \([9,9]\) you need to check \[f(9),f(\frac{2}{15}), f(8), f(9)\]
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.0
got it. thank you!
 one year ago
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