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mathcalculus
 2 years ago
locate the critical points: g(x)= (1*x+1)/17x
mathcalculus
 2 years ago
locate the critical points: g(x)= (1*x+1)/17x

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mathcalculus
 2 years ago
Best ResponseYou've already chosen the best response.1so far im left with : 7x^27x6

mathcalculus
 2 years ago
Best ResponseYou've already chosen the best response.1i know that i have to = to zero

Peter14
 2 years ago
Best ResponseYou've already chosen the best response.0could you write out the equation more clearly?

mathcalculus
 2 years ago
Best ResponseYou've already chosen the best response.1g(x) \[\frac{ 1*x+1 }{17x}\]

Peter14
 2 years ago
Best ResponseYou've already chosen the best response.0then you use quotient rule?

mathcalculus
 2 years ago
Best ResponseYou've already chosen the best response.1i found the derivative..

mathcalculus
 2 years ago
Best ResponseYou've already chosen the best response.1@mattt9 the derivative that i got is this: \[\frac{ 1*(17x)7(x+1) }{ (17x)^{2} }\]

mathcalculus
 2 years ago
Best ResponseYou've already chosen the best response.1how did i get the derivative wrong?

Peter14
 2 years ago
Best ResponseYou've already chosen the best response.0matt, I don't think you can take away the ^2 like that...

mattt9
 2 years ago
Best ResponseYou've already chosen the best response.0hmm i think you're right actually.

mathcalculus
 2 years ago
Best ResponseYou've already chosen the best response.1the answer is none

mattt9
 2 years ago
Best ResponseYou've already chosen the best response.0okay that's what i thought.

mattt9
 2 years ago
Best ResponseYou've already chosen the best response.0after peter reclarified that for me

mathcalculus
 2 years ago
Best ResponseYou've already chosen the best response.1x cannot be 1/7 because you cancel the 7x+7x and youre left with 6

Peter14
 2 years ago
Best ResponseYou've already chosen the best response.0graphing\[y=\frac{ 1 }{ (17x)^2 }\] with Desmos I don't see a place where it crosses the Xaxis

mathcalculus
 2 years ago
Best ResponseYou've already chosen the best response.1when you multiply the denominator to zero= 0

mathcalculus
 2 years ago
Best ResponseYou've already chosen the best response.1and 6 does not equal to an x

Peter14
 2 years ago
Best ResponseYou've already chosen the best response.0thinking about it: 1/anything cannot equal 0

Peter14
 2 years ago
Best ResponseYou've already chosen the best response.0so there are no critical points
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