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where is everyone?!? help please! =( find the extrema: 4x^3-13x^2+4x+1 max and min: [1,4] [0,2]

Mathematics
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i put the answer: [1,4] max=65 min= -11 and for [0,2] max= 196 min= -11 what's wrong with the answer?
i found the derivative..12x^2-26x+4
then i factored: and got the critical points: x=1/6 and x=2

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then i evaluated f at each critical number
and then evaluated f at each endpoints
left point: critical points: Right point: f(1) -4 f(1/6)= 1.32407 f(4)= 65 f(0)=1 f(2)= -11 f(5)= 196
now can anyone tell me what i did wrong with the answer? [1,4] max=65 min= -11 [0,2] max= 196 min= -11
iam here
why you took f(5) ?
range is [0,2] right ?
sorry everyone.... hehe
so for for [0,2] max= 1min= -11
i see nothing else wrong besides f(5)
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hmm, critical points are x=1/6, 2 so local max/min are f(1/6) and f(2) max = f(1/6) = 1.3 min = f(2) = -11
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raised by bats
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yup, i appreciate all the help.
okay.....

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