mathcalculus
where is everyone?!? help please! =(
find the extrema: 4x^313x^2+4x+1
max and min:
[1,4]
[0,2]



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mathcalculus
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i put the answer: [1,4] max=65 min= 11 and for [0,2] max= 196 min= 11
what's wrong with the answer?

mathcalculus
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i found the derivative..12x^226x+4

mathcalculus
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then i factored: and got the critical points: x=1/6 and x=2

mathcalculus
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then i evaluated f at each critical number

mathcalculus
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and then evaluated f at each endpoints

mathcalculus
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left point: critical points: Right point:
f(1) 4 f(1/6)= 1.32407 f(4)= 65
f(0)=1 f(2)= 11 f(5)= 196

mathcalculus
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now can anyone tell me what i did wrong with the answer?
[1,4] max=65 min= 11
[0,2] max= 196 min= 11

mathcalculus
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@hartnn :(

mathcalculus
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@dan815

mathcalculus
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@wio

dan815
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iam here

hartnn
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why you took f(5) ?

hartnn
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range is [0,2] right ?

mathcalculus
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sorry everyone.... hehe

hartnn
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so for for [0,2] max= 1min= 11

dan815
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i see nothing else wrong besides f(5)

mathcalculus
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dw:1363331661154:dw

dan815
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dw:1363331762488:dw

dan815
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dw:1363331811355:dw

mathcalculus
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dw:1363331917359:dw

dumbcow
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hmm, critical points are x=1/6, 2
so local max/min are f(1/6) and f(2)
max = f(1/6) = 1.3
min = f(2) = 11

dan815
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dw:1363331991812:dw

dan815
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u got one of those stupid owls

dan815
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raised by bats

mathcalculus
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?

mathcalculus
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dw:1363332131809:dw

dan815
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thankyou for becoming my fan :D

dan815
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as a gift id like to tell you the name of God is JESUS treasure it

mathcalculus
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yup, i appreciate all the help.

mathcalculus
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okay.....