anonymous
  • anonymous
where is everyone?!? help please! =( find the extrema: 4x^3-13x^2+4x+1 max and min: [1,4] [0,2]
Mathematics
schrodinger
  • schrodinger
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schrodinger
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anonymous
  • anonymous
i put the answer: [1,4] max=65 min= -11 and for [0,2] max= 196 min= -11 what's wrong with the answer?
anonymous
  • anonymous
i found the derivative..12x^2-26x+4
anonymous
  • anonymous
then i factored: and got the critical points: x=1/6 and x=2

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anonymous
  • anonymous
then i evaluated f at each critical number
anonymous
  • anonymous
and then evaluated f at each endpoints
anonymous
  • anonymous
left point: critical points: Right point: f(1) -4 f(1/6)= 1.32407 f(4)= 65 f(0)=1 f(2)= -11 f(5)= 196
anonymous
  • anonymous
now can anyone tell me what i did wrong with the answer? [1,4] max=65 min= -11 [0,2] max= 196 min= -11
anonymous
  • anonymous
@hartnn :(
anonymous
  • anonymous
@dan815
anonymous
  • anonymous
@wio
dan815
  • dan815
iam here
hartnn
  • hartnn
why you took f(5) ?
hartnn
  • hartnn
range is [0,2] right ?
anonymous
  • anonymous
sorry everyone.... hehe
hartnn
  • hartnn
so for for [0,2] max= 1min= -11
dan815
  • dan815
i see nothing else wrong besides f(5)
anonymous
  • anonymous
|dw:1363331661154:dw|
dan815
  • dan815
|dw:1363331762488:dw|
dan815
  • dan815
|dw:1363331811355:dw|
anonymous
  • anonymous
|dw:1363331917359:dw|
dumbcow
  • dumbcow
hmm, critical points are x=1/6, 2 so local max/min are f(1/6) and f(2) max = f(1/6) = 1.3 min = f(2) = -11
dan815
  • dan815
|dw:1363331991812:dw|
dan815
  • dan815
u got one of those stupid owls
dan815
  • dan815
raised by bats
anonymous
  • anonymous
?
anonymous
  • anonymous
|dw:1363332131809:dw|
dan815
  • dan815
thankyou for becoming my fan :D
dan815
  • dan815
as a gift id like to tell you the name of God is JESUS treasure it
anonymous
  • anonymous
yup, i appreciate all the help.
anonymous
  • anonymous
okay.....

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