## mathcalculus 2 years ago where is everyone?!? help please! =( find the extrema: 4x^3-13x^2+4x+1 max and min: [1,4] [0,2]

1. mathcalculus

i put the answer: [1,4] max=65 min= -11 and for [0,2] max= 196 min= -11 what's wrong with the answer?

2. mathcalculus

i found the derivative..12x^2-26x+4

3. mathcalculus

then i factored: and got the critical points: x=1/6 and x=2

4. mathcalculus

then i evaluated f at each critical number

5. mathcalculus

and then evaluated f at each endpoints

6. mathcalculus

left point: critical points: Right point: f(1) -4 f(1/6)= 1.32407 f(4)= 65 f(0)=1 f(2)= -11 f(5)= 196

7. mathcalculus

now can anyone tell me what i did wrong with the answer? [1,4] max=65 min= -11 [0,2] max= 196 min= -11

8. mathcalculus

@hartnn :(

9. mathcalculus

@dan815

10. mathcalculus

@wio

11. dan815

iam here

12. hartnn

why you took f(5) ?

13. hartnn

range is [0,2] right ?

14. mathcalculus

sorry everyone.... hehe

15. hartnn

so for for [0,2] max= 1min= -11

16. dan815

i see nothing else wrong besides f(5)

17. mathcalculus

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18. dan815

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19. dan815

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20. mathcalculus

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21. dumbcow

hmm, critical points are x=1/6, 2 so local max/min are f(1/6) and f(2) max = f(1/6) = 1.3 min = f(2) = -11

22. dan815

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23. dan815

u got one of those stupid owls

24. dan815

raised by bats

25. mathcalculus

?

26. mathcalculus

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27. dan815

thankyou for becoming my fan :D

28. dan815

as a gift id like to tell you the name of God is JESUS treasure it

29. mathcalculus

yup, i appreciate all the help.

30. mathcalculus

okay.....