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mathcalculus
Group Title
where is everyone?!? help please! =(
find the extrema: 4x^313x^2+4x+1
max and min:
[1,4]
[0,2]
 one year ago
 one year ago
mathcalculus Group Title
where is everyone?!? help please! =( find the extrema: 4x^313x^2+4x+1 max and min: [1,4] [0,2]
 one year ago
 one year ago

This Question is Closed

mathcalculus Group TitleBest ResponseYou've already chosen the best response.1
i put the answer: [1,4] max=65 min= 11 and for [0,2] max= 196 min= 11 what's wrong with the answer?
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.1
i found the derivative..12x^226x+4
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.1
then i factored: and got the critical points: x=1/6 and x=2
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.1
then i evaluated f at each critical number
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.1
and then evaluated f at each endpoints
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.1
left point: critical points: Right point: f(1) 4 f(1/6)= 1.32407 f(4)= 65 f(0)=1 f(2)= 11 f(5)= 196
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.1
now can anyone tell me what i did wrong with the answer? [1,4] max=65 min= 11 [0,2] max= 196 min= 11
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.1
@hartnn :(
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.1
@dan815
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
why you took f(5) ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
range is [0,2] right ?
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.1
sorry everyone.... hehe
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
so for for [0,2] max= 1min= 11
 one year ago

dan815 Group TitleBest ResponseYou've already chosen the best response.0
i see nothing else wrong besides f(5)
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.1
dw:1363331661154:dw
 one year ago

dan815 Group TitleBest ResponseYou've already chosen the best response.0
dw:1363331762488:dw
 one year ago

dan815 Group TitleBest ResponseYou've already chosen the best response.0
dw:1363331811355:dw
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.1
dw:1363331917359:dw
 one year ago

dumbcow Group TitleBest ResponseYou've already chosen the best response.0
hmm, critical points are x=1/6, 2 so local max/min are f(1/6) and f(2) max = f(1/6) = 1.3 min = f(2) = 11
 one year ago

dan815 Group TitleBest ResponseYou've already chosen the best response.0
dw:1363331991812:dw
 one year ago

dan815 Group TitleBest ResponseYou've already chosen the best response.0
u got one of those stupid owls
 one year ago

dan815 Group TitleBest ResponseYou've already chosen the best response.0
raised by bats
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.1
dw:1363332131809:dw
 one year ago

dan815 Group TitleBest ResponseYou've already chosen the best response.0
thankyou for becoming my fan :D
 one year ago

dan815 Group TitleBest ResponseYou've already chosen the best response.0
as a gift id like to tell you the name of God is JESUS treasure it
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.1
yup, i appreciate all the help.
 one year ago

mathcalculus Group TitleBest ResponseYou've already chosen the best response.1
okay.....
 one year ago
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