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Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.3\[\int\limits_{0}^{4}(1\sqrt{u})/(\sqrt{u})\]

Azteck
 one year ago
Best ResponseYou've already chosen the best response.0Lolz...didn't even neded to substitute.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Yah the substitution was kinda silly :) If you do a substitution, don't forget to change the limits of integration also.

Azteck
 one year ago
Best ResponseYou've already chosen the best response.0And there's no du at the back of the integral

Azteck
 one year ago
Best ResponseYou've already chosen the best response.0You can't continue on integrating that without respect of anything.

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.3Ops, sorry forgot about the du.. It is in respect to du

Azteck
 one year ago
Best ResponseYou've already chosen the best response.0What are you integrating with respect to? You integrating with respect to zero?

Azteck
 one year ago
Best ResponseYou've already chosen the best response.0Okay. Now you can integrate it. Just separate the numerator.

Azteck
 one year ago
Best ResponseYou've already chosen the best response.0And you can continue integrating per usual.

Lynncake
 one year ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{}^{}\frac{ 1 }{ \sqrt{u} }du\int\limits_{}^{}1du\]\[\int\limits_{}^{}u^{\frac{ 1 }{ 2 }}duu\]\[2u^{\frac{ 1 }{ 2 }}u\]Then just plug in the limit from 0 to 4

Luigi0210
 one year ago
Best ResponseYou've already chosen the best response.3My only real problem is finding the antiderivative

Azteck
 one year ago
Best ResponseYou've already chosen the best response.0Antidifferentiating is just differentiating in reverse. Try and use reverse psychology when integrating if you can.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1\[\large \frac{1\sqrt u}{\sqrt u} \qquad = \qquad \frac{1}{\sqrt u}\frac{\sqrt u}{\sqrt u} \qquad = \qquad u^{1/2}1\] Yah you just apply the `Power Rule for Integration`! :D
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