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Luigi0210Best ResponseYou've already chosen the best response.3
\[\int\limits_{0}^{4}(1\sqrt{u})/(\sqrt{u})\]
 one year ago

AzteckBest ResponseYou've already chosen the best response.0
Lolz...didn't even neded to substitute.
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
Yah the substitution was kinda silly :) If you do a substitution, don't forget to change the limits of integration also.
 one year ago

AzteckBest ResponseYou've already chosen the best response.0
And there's no du at the back of the integral
 one year ago

AzteckBest ResponseYou've already chosen the best response.0
You can't continue on integrating that without respect of anything.
 one year ago

Luigi0210Best ResponseYou've already chosen the best response.3
Ops, sorry forgot about the du.. It is in respect to du
 one year ago

AzteckBest ResponseYou've already chosen the best response.0
What are you integrating with respect to? You integrating with respect to zero?
 one year ago

AzteckBest ResponseYou've already chosen the best response.0
Okay. Now you can integrate it. Just separate the numerator.
 one year ago

AzteckBest ResponseYou've already chosen the best response.0
And you can continue integrating per usual.
 one year ago

LynncakeBest ResponseYou've already chosen the best response.0
\[\int\limits_{}^{}\frac{ 1 }{ \sqrt{u} }du\int\limits_{}^{}1du\]\[\int\limits_{}^{}u^{\frac{ 1 }{ 2 }}duu\]\[2u^{\frac{ 1 }{ 2 }}u\]Then just plug in the limit from 0 to 4
 one year ago

Luigi0210Best ResponseYou've already chosen the best response.3
My only real problem is finding the antiderivative
 one year ago

AzteckBest ResponseYou've already chosen the best response.0
Antidifferentiating is just differentiating in reverse. Try and use reverse psychology when integrating if you can.
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
\[\large \frac{1\sqrt u}{\sqrt u} \qquad = \qquad \frac{1}{\sqrt u}\frac{\sqrt u}{\sqrt u} \qquad = \qquad u^{1/2}1\] Yah you just apply the `Power Rule for Integration`! :D
 one year ago
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