A community for students.
Here's the question you clicked on:
 0 viewing
Luigi0210
 2 years ago
solve the integral
Luigi0210
 2 years ago
solve the integral

This Question is Closed

Luigi0210
 2 years ago
Best ResponseYou've already chosen the best response.3\[\int\limits_{0}^{4}(1\sqrt{u})/(\sqrt{u})\]

Azteck
 2 years ago
Best ResponseYou've already chosen the best response.0Lolz...didn't even neded to substitute.

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1Yah the substitution was kinda silly :) If you do a substitution, don't forget to change the limits of integration also.

Azteck
 2 years ago
Best ResponseYou've already chosen the best response.0And there's no du at the back of the integral

Azteck
 2 years ago
Best ResponseYou've already chosen the best response.0You can't continue on integrating that without respect of anything.

Luigi0210
 2 years ago
Best ResponseYou've already chosen the best response.3Ops, sorry forgot about the du.. It is in respect to du

Azteck
 2 years ago
Best ResponseYou've already chosen the best response.0What are you integrating with respect to? You integrating with respect to zero?

Azteck
 2 years ago
Best ResponseYou've already chosen the best response.0Okay. Now you can integrate it. Just separate the numerator.

Azteck
 2 years ago
Best ResponseYou've already chosen the best response.0And you can continue integrating per usual.

Lynncake
 2 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{}^{}\frac{ 1 }{ \sqrt{u} }du\int\limits_{}^{}1du\]\[\int\limits_{}^{}u^{\frac{ 1 }{ 2 }}duu\]\[2u^{\frac{ 1 }{ 2 }}u\]Then just plug in the limit from 0 to 4

Luigi0210
 2 years ago
Best ResponseYou've already chosen the best response.3My only real problem is finding the antiderivative

Azteck
 2 years ago
Best ResponseYou've already chosen the best response.0Antidifferentiating is just differentiating in reverse. Try and use reverse psychology when integrating if you can.

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1\[\large \frac{1\sqrt u}{\sqrt u} \qquad = \qquad \frac{1}{\sqrt u}\frac{\sqrt u}{\sqrt u} \qquad = \qquad u^{1/2}1\] Yah you just apply the `Power Rule for Integration`! :D
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.