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work done force * distance.

lol forgot that equal after work done..
*work done =force * perpendicular distance.

Okay well can you help me start up the equation because I'm completely lost...:O

|dw:1363361078018:dw|

which is prolly redundant information, we already know the force and the distance that it moved.

.... an additional 3 inches eh we would need to recalculate the Force then right?

\[750=-k(3)\]
\[\frac{750}{3}=-k\]
\[F_{new}=\frac{750}{3}(3+3)\]right?

Okay and that is the work done :) Thanks man! :D

Why is W= 750/9 shouldnt it be 750/3?

then times by (6^3-3^3)

no, you are prolly not familiar with integration if you ask that question

Okay...What exactly are the units?

Ohhh okay thanks. :)

the units will still be pounds per inches

pounds per square inches that is

Okay thanks man! :D

So 15,750 pounds per square in.

Okay so how would I change it to N
ewtons?

conversions arent in my memory .... might have to google a conversion :)

Okay thanks anyways! :D

Work is normally expressed in Newtons per meter

so newtons to pounds and inches to meters would be the conversion

Yeah it gave me this 2758247.65125 per Newton Meter

http://www.convertunits.com/from/pounds+per+inch/to/newton/metre

Thats the website I used to convert.

\[\frac{1575lbs*in}{1}\frac{.0254m}{1in}*\frac{4.448N}{1lbs}=177.94~Nm\]

my mistake was in the lbs/in,,, its lbs x inches

Okay so its x not *

lol .... and i seemed to have dropped a 0 on the end, 15750

Haha okay thanks :)

So the answer is 17,794.2Nm ;D