Quantcast

A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

zerosniper123

  • 2 years ago

I'm completely lost...can someone show me the steps on how to solve these... A force of 750 pounds compresses a spring 3 inches from its natural length of 15 inches. Find the work done in compressing the spring an additional 3 inches.

  • This Question is Closed
  1. nubeer
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    work done force * distance.

  2. nubeer
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    lol forgot that equal after work done.. *work done =force * perpendicular distance.

  3. zerosniper123
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Okay well can you help me start up the equation because I'm completely lost...:O

  4. nubeer
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    it has told u 750 is the force which is not going to cahnge .. so now u just have to find the distance the spring is going to compressed.

  5. amistre64
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1363361078018:dw|

  6. amistre64
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    which is prolly redundant information, we already know the force and the distance that it moved.

  7. amistre64
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    .... an additional 3 inches eh we would need to recalculate the Force then right?

  8. amistre64
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    \[750=-k(3)\] \[\frac{750}{3}=-k\] \[F_{new}=\frac{750}{3}(3+3)\]right?

  9. amistre64
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    since the force to move the spring varies across its distance, we could use integration to determine the total amount of work done .... if you believe that the question is asking for a more complicated result

  10. amistre64
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    \[W=\int Fxd\] \[W=\int_a^b(-kx)x~dx\] \[W=\int_{3}^{6}\frac{750}{3}x^2~dx\] \[W=\frac{750}{9}(6^3-3^3)\]

  11. zerosniper123
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Okay and that is the work done :) Thanks man! :D

  12. zerosniper123
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Why is W= 750/9 shouldnt it be 750/3?

  13. zerosniper123
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    then times by (6^3-3^3)

  14. amistre64
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    no, you are prolly not familiar with integration if you ask that question

  15. zerosniper123
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Okay...What exactly are the units?

  16. amistre64
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    in effect: to integrate a variable, you want to increase the exponent by 1, and divide by the new exponent \[\int~x\ dx=\frac{x^2}{2}\]

  17. zerosniper123
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ohhh okay thanks. :)

  18. amistre64
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    the units will still be pounds per inches

  19. amistre64
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    pounds per square inches that is

  20. zerosniper123
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Okay thanks man! :D

  21. zerosniper123
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    So 15,750 pounds per square in.

  22. amistre64
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Force over a Distance .... nah, its just pounds per inch you might want to make it more presentable tho and convert it to Newtons of something

  23. zerosniper123
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Okay so how would I change it to N ewtons?

  24. amistre64
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    conversions arent in my memory .... might have to google a conversion :)

  25. zerosniper123
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Okay thanks anyways! :D

  26. amistre64
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Work is normally expressed in Newtons per meter

  27. amistre64
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    so newtons to pounds and inches to meters would be the conversion

  28. zerosniper123
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yeah it gave me this 2758247.65125 per Newton Meter

  29. zerosniper123
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    http://www.convertunits.com/from/pounds+per+inch/to/newton/metre

  30. zerosniper123
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Thats the website I used to convert.

  31. amistre64
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    \[\frac{1575lbs*in}{1}\frac{.0254m}{1in}*\frac{4.448N}{1lbs}=177.94~Nm\]

  32. amistre64
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    my mistake was in the lbs/in,,, its lbs x inches

  33. zerosniper123
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Okay so its x not *

  34. amistre64
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    more like: \[\cancel{\frac{1575~lbs}{1in}}\to1575~lbs~in\] "per" is divisiion and we didnt divide .. we multiplied

  35. amistre64
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    lol .... and i seemed to have dropped a 0 on the end, 15750

  36. zerosniper123
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Haha okay thanks :)

  37. zerosniper123
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    So the answer is 17,794.2Nm ;D

  38. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.