anonymous
  • anonymous
integration- radicals
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
?
anonymous
  • anonymous
\[\color{blue}{\huge\int_0^1\sqrt[3]{1-x^7}-\sqrt[7]{1-x^3}dx}\]
UnkleRhaukus
  • UnkleRhaukus
\[\color{blue}{\int_0^1\sqrt[3]{1-x^7}dx-\int\sqrt[7]{1-x^3}dx}\]

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anonymous
  • anonymous
yes but when i do that it still seems ugly
UnkleRhaukus
  • UnkleRhaukus
do one half at a time
anonymous
  • anonymous
i shud make a u sub \[u=1-x^7\]
anonymous
  • anonymous
in the 1st one
UnkleRhaukus
  • UnkleRhaukus
i'd say so
anonymous
  • anonymous
\[u=1-x^7\] \[\int\frac{u^{1/3}}{7x^6}du\]
anonymous
  • anonymous
the x^6 is a problem
anonymous
  • anonymous
\[\int\frac{u^{1/3}}{7(1-u)^{1/7}}\]
UnkleRhaukus
  • UnkleRhaukus
hmm,
UnkleRhaukus
  • UnkleRhaukus
maybe that method isn't going to work
anonymous
  • anonymous
http://www.wolframalpha.com/input/?i=integral+%281-x%5E7%29%5E%7B1%2F3%7D-%281-x%5E3%29%5E%7B1%2F7%7D ugly as well but i think we are supposed to use 'by parts'
UnkleRhaukus
  • UnkleRhaukus
where did you get this question?
anonymous
  • anonymous
http://books.google.com.tr/books?id=v4-1Rk7uaEcC&pg=PA618&hl=tr&source=gbs_toc_r&cad=4#v=onepage&q&f=false
anonymous
  • anonymous
steward calculus advanved problem
anonymous
  • anonymous
*
shubhamsrg
  • shubhamsrg
what if we use the property integral ( f(x) from x=a to b = f(a+b-x) from x= a to b )?
anonymous
  • anonymous
in this case a+b=0+1 int f(1-x)=f(x)
shubhamsrg
  • shubhamsrg
yep, am not too sure if that'll work though, but probably should work ?
anonymous
  • anonymous
ok i have to go i;ll try it thanks to everyone for the effort
anonymous
  • anonymous
According to WA, the definite integral is 0: http://www.wolframalpha.com/input/?i=integrate+%28%281-x%5E7%29%5E%281%2F3%29+-+%281-x%5E3%29%5E%281%2F7%29%29+over+%5B0%2C1%5D Maybe there's some detail we're not getting about the function itself.
anonymous
  • anonymous
interesting result maybe this property is because of the function is actually an inverse of itself i mean \[f(x)=\sqrt[3]{1-x^7}\] then \[f^{-1}(x)=\sqrt[7]{1-x^3}\] should this mean anything
anonymous
  • anonymous
\[\int_0^1 f(x)-f^{-1}(x) \space dx\] \[f(1)=f^{-1}(1)=0\]
experimentX
  • experimentX
this is a famous question on M.SE
experimentX
  • experimentX
http://math.stackexchange.com/questions/139393/how-to-show-that-int-01-left-sqrt31-x7-sqrt71-x3-right-dx/139398#139398

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