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amstro

  • one year ago

If A, B and C are the angles of a triangle, prove that sinBcosC+cosBsinC=sinA

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  1. Hope_nicole
    • one year ago
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    Plug in an angle for each

  2. sauravshakya
    • one year ago
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    A+B+C=180 A+B=180-C sin(A+B)=sin(180-C) sinBcosC+cosBsinC=sinA

  3. sauravshakya
    • one year ago
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    got it?

  4. amstro
    • one year ago
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    @sauravshakya could you explain the step between sin(A+B)=sin(180-C) sinBcosC+cosBsinC=sinA So sorry and thannks

  5. sauravshakya
    • one year ago
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    Looks like I did a simple mistake, A+B+C=180 B+C=180-A sin(B+C)=sin(180-A) sinBcosC+cosBsinC=sinA

  6. amstro
    • one year ago
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    Thanks alot!

  7. sauravshakya
    • one year ago
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    welcome

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