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If A, B and C are the angles of a triangle, prove that sinBcosC+cosBsinC=sinA
 one year ago
 one year ago
If A, B and C are the angles of a triangle, prove that sinBcosC+cosBsinC=sinA
 one year ago
 one year ago

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Hope_nicoleBest ResponseYou've already chosen the best response.0
Plug in an angle for each
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
A+B+C=180 A+B=180C sin(A+B)=sin(180C) sinBcosC+cosBsinC=sinA
 one year ago

amstroBest ResponseYou've already chosen the best response.1
@sauravshakya could you explain the step between sin(A+B)=sin(180C) sinBcosC+cosBsinC=sinA So sorry and thannks
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
Looks like I did a simple mistake, A+B+C=180 B+C=180A sin(B+C)=sin(180A) sinBcosC+cosBsinC=sinA
 one year ago
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