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amstro
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If A, B and C are the angles of a triangle, prove that sinBcosC+cosBsinC=sinA
 one year ago
 one year ago
amstro Group Title
If A, B and C are the angles of a triangle, prove that sinBcosC+cosBsinC=sinA
 one year ago
 one year ago

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Hope_nicole Group TitleBest ResponseYou've already chosen the best response.0
Plug in an angle for each
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
A+B+C=180 A+B=180C sin(A+B)=sin(180C) sinBcosC+cosBsinC=sinA
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
got it?
 one year ago

amstro Group TitleBest ResponseYou've already chosen the best response.1
@sauravshakya could you explain the step between sin(A+B)=sin(180C) sinBcosC+cosBsinC=sinA So sorry and thannks
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
Looks like I did a simple mistake, A+B+C=180 B+C=180A sin(B+C)=sin(180A) sinBcosC+cosBsinC=sinA
 one year ago

amstro Group TitleBest ResponseYou've already chosen the best response.1
Thanks alot!
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
welcome
 one year ago
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