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anonymous
 3 years ago
By using the method [acosθ+bsinθ=ccos(θ+α)] Find values of θ up to 360 degrees from equation 2sinθ+4cosθ=√5
anonymous
 3 years ago
By using the method [acosθ+bsinθ=ccos(θ+α)] Find values of θ up to 360 degrees from equation 2sinθ+4cosθ=√5

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Let 2sin/theta/ +4 cos/theta/ = rcos(theta + alpha) then 2sin/theta/ + 4cos/theta/ = r(costheta * cosalpha  sintheta * sinalpha) 2 sin/theta/ + 4cos/theta/ = (r*sinalpha)sin/theta/ + (r cosalpha) cos/theta/ =>rsinalpha =2 =>r cosalpha =4

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Now, can u find r and alpha?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes should be ok from here. Thats great thanks

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Just gone through it again fully got it now thanks again. Very quick math from you
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