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jimswig88

By using the method [acosθ+bsinθ=ccos(θ+α)] Find values of θ up to 360 degrees from equation 2sinθ+4cosθ=√5

  • one year ago
  • one year ago

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  1. sauravshakya
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    Let 2sin/theta/ +4 cos/theta/ = rcos(theta + alpha) then 2sin/theta/ + 4cos/theta/ = r(costheta * cosalpha - sintheta * sinalpha) 2 sin/theta/ + 4cos/theta/ = (-r*sinalpha)sin/theta/ + (r cosalpha) cos/theta/ =>-rsinalpha =2 =>r cosalpha =4

    • one year ago
  2. sauravshakya
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    Now, can u find r and alpha?

    • one year ago
  3. jimswig88
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    Yes should be ok from here. Thats great thanks

    • one year ago
  4. sauravshakya
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    welcome

    • one year ago
  5. jimswig88
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    Just gone through it again fully got it now thanks again. Very quick math from you

    • one year ago
  6. sauravshakya
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    welcome again

    • one year ago
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