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 one year ago
By using the method [acosθ+bsinθ=ccos(θ+α)] Find values of θ up to 360 degrees from equation 2sinθ+4cosθ=√5
 one year ago
By using the method [acosθ+bsinθ=ccos(θ+α)] Find values of θ up to 360 degrees from equation 2sinθ+4cosθ=√5

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sauravshakya
 one year ago
Best ResponseYou've already chosen the best response.1Let 2sin/theta/ +4 cos/theta/ = rcos(theta + alpha) then 2sin/theta/ + 4cos/theta/ = r(costheta * cosalpha  sintheta * sinalpha) 2 sin/theta/ + 4cos/theta/ = (r*sinalpha)sin/theta/ + (r cosalpha) cos/theta/ =>rsinalpha =2 =>r cosalpha =4

sauravshakya
 one year ago
Best ResponseYou've already chosen the best response.1Now, can u find r and alpha?

jimswig88
 one year ago
Best ResponseYou've already chosen the best response.1Yes should be ok from here. Thats great thanks

jimswig88
 one year ago
Best ResponseYou've already chosen the best response.1Just gone through it again fully got it now thanks again. Very quick math from you
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