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mskyeg

Graph the conic section. 25x^2 – 16y^2 = 400

  • one year ago
  • one year ago

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  1. mskyeg
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    • one year ago
  2. Mertsj
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    Put it into the proper form by dividing both sides by 400.

    • one year ago
  3. mskyeg
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    got it

    • one year ago
  4. Mertsj
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    ok. Good for you.

    • one year ago
  5. mskyeg
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    now what

    • one year ago
  6. Mertsj
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    Oh. ok. Identify a and b

    • one year ago
  7. mskyeg
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    I think a is 25 and b is 16

    • one year ago
  8. mskyeg
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    does a^2=25 or a=25

    • one year ago
  9. Compassionate
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    You subtract 400. Not divide it

    • one year ago
  10. Mertsj
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    \[\frac{x^2}{16}-\frac{y^2}{25}=1\]

    • one year ago
  11. mskyeg
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    ya thats wat i got

    • one year ago
  12. Mertsj
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    No compassionate. You are incorrect and we have it handled.

    • one year ago
  13. mskyeg
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    how does that translate to the graph?

    • one year ago
  14. Mertsj
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    It is important to note that x cannot be 0. Is that clear to you?

    • one year ago
  15. mskyeg
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    ya

    • one year ago
  16. Mertsj
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    So if x cannot be 0, the hyperbola cannot cross the y axis. So that eliminates the last two choices.

    • one year ago
  17. Mertsj
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    And so since 16 is a^2, a is 4 so the vertices are 4 and -4 and there is only one choice that has those vertices.

    • one year ago
  18. mskyeg
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    the first one?

    • one year ago
  19. Mertsj
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    yep

    • one year ago
  20. mskyeg
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    yay! thanks:)

    • one year ago
  21. Mertsj
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    yw

    • one year ago
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