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Mertsj Group TitleBest ResponseYou've already chosen the best response.3
Put it into the proper form by dividing both sides by 400.
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.3
ok. Good for you.
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.3
Oh. ok. Identify a and b
 one year ago

mskyeg Group TitleBest ResponseYou've already chosen the best response.0
I think a is 25 and b is 16
 one year ago

mskyeg Group TitleBest ResponseYou've already chosen the best response.0
does a^2=25 or a=25
 one year ago

Compassionate Group TitleBest ResponseYou've already chosen the best response.0
You subtract 400. Not divide it
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.3
\[\frac{x^2}{16}\frac{y^2}{25}=1\]
 one year ago

mskyeg Group TitleBest ResponseYou've already chosen the best response.0
ya thats wat i got
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.3
No compassionate. You are incorrect and we have it handled.
 one year ago

mskyeg Group TitleBest ResponseYou've already chosen the best response.0
how does that translate to the graph?
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.3
It is important to note that x cannot be 0. Is that clear to you?
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.3
So if x cannot be 0, the hyperbola cannot cross the y axis. So that eliminates the last two choices.
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.3
And so since 16 is a^2, a is 4 so the vertices are 4 and 4 and there is only one choice that has those vertices.
 one year ago

mskyeg Group TitleBest ResponseYou've already chosen the best response.0
the first one?
 one year ago

mskyeg Group TitleBest ResponseYou've already chosen the best response.0
yay! thanks:)
 one year ago
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