## mskyeg Group Title Graph the conic section. 25x^2 – 16y^2 = 400 one year ago one year ago

1. mskyeg

2. Mertsj

Put it into the proper form by dividing both sides by 400.

3. mskyeg

got it

4. Mertsj

ok. Good for you.

5. mskyeg

now what

6. Mertsj

Oh. ok. Identify a and b

7. mskyeg

I think a is 25 and b is 16

8. mskyeg

does a^2=25 or a=25

9. Compassionate

You subtract 400. Not divide it

10. Mertsj

$\frac{x^2}{16}-\frac{y^2}{25}=1$

11. mskyeg

ya thats wat i got

12. Mertsj

No compassionate. You are incorrect and we have it handled.

13. mskyeg

how does that translate to the graph?

14. Mertsj

It is important to note that x cannot be 0. Is that clear to you?

15. mskyeg

ya

16. Mertsj

So if x cannot be 0, the hyperbola cannot cross the y axis. So that eliminates the last two choices.

17. Mertsj

And so since 16 is a^2, a is 4 so the vertices are 4 and -4 and there is only one choice that has those vertices.

18. mskyeg

the first one?

19. Mertsj

yep

20. mskyeg

yay! thanks:)

21. Mertsj

yw