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Weights of apples grown in an orchard are known to follow a normal distribution with mean 160 grams. It is known that approximately 99.7% of apples have weights between124 and 196 grams. What is the standard deviation of weights of all apples grown in the orchard?
 one year ago
 one year ago
Weights of apples grown in an orchard are known to follow a normal distribution with mean 160 grams. It is known that approximately 99.7% of apples have weights between124 and 196 grams. What is the standard deviation of weights of all apples grown in the orchard?
 one year ago
 one year ago

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yashar806Best ResponseYou've already chosen the best response.0
but i cant get the right answer
 one year ago

yashar806Best ResponseYou've already chosen the best response.0
i used that that formula
 one year ago

tomoBest ResponseYou've already chosen the best response.0
z1 = (124160)/sigma z2 = (196160)/sigma 1z1z2 = (99.7)/100
 one year ago

tomoBest ResponseYou've already chosen the best response.0
i have to leave, but I think that should help you find the answer
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
dont we just need one of those to determine sigma?
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
\[z=\frac{x\bar x}{sd}\] \[sd=\frac{x\bar x}{z}\]
 one year ago

yashar806Best ResponseYou've already chosen the best response.0
why we need to 1 them
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
or rather, we dont have the z value explicitly do we
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
dw:1363377005023:dw
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
we have an implicit z, we can either use the zscore of .3/2 .. or 99.7+.3/2
 one year ago

yashar806Best ResponseYou've already chosen the best response.0
what would be answer?
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
does that make sense? 99.7% is inbetween those values, so the proper zscore has to be adjusted. use z(.9985), at x=196 or, z(.0015), at x=124
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
id prolly use the 196 version
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
can you tell me the zscore of .9985?
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
i agree soo, sd= (196160)/2.96
 one year ago

yashar806Best ResponseYou've already chosen the best response.0
can we use both of them?
 one year ago

yashar806Best ResponseYou've already chosen the best response.0
z1 = (124160)/sigma z2 = (196160)/sigma
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
we can, the sd will be negative for the z1 equation and the percentage at z1 is (.0015), iinstead of (.9985)
 one year ago

yashar806Best ResponseYou've already chosen the best response.0
thats wht i used initially
 one year ago

yashar806Best ResponseYou've already chosen the best response.0
but i got wrong answer
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
one chk would be to do (124160)/12.1622 and see if its about .0015 :)
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
hmm, i get 2.96 is 160 by chance the average of 124 and 196?
 one year ago
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