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yashar806
 2 years ago
Weights of apples grown in an orchard are known to follow a normal distribution with mean 160 grams. It is known that approximately 99.7% of apples have weights between124 and 196 grams. What is the standard deviation of weights of all apples grown in the orchard?
yashar806
 2 years ago
Weights of apples grown in an orchard are known to follow a normal distribution with mean 160 grams. It is known that approximately 99.7% of apples have weights between124 and 196 grams. What is the standard deviation of weights of all apples grown in the orchard?

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yashar806
 2 years ago
Best ResponseYou've already chosen the best response.0but i cant get the right answer

yashar806
 2 years ago
Best ResponseYou've already chosen the best response.0i used that that formula

tomo
 2 years ago
Best ResponseYou've already chosen the best response.0z1 = (124160)/sigma z2 = (196160)/sigma 1z1z2 = (99.7)/100

tomo
 2 years ago
Best ResponseYou've already chosen the best response.0i have to leave, but I think that should help you find the answer

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0dont we just need one of those to determine sigma?

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0\[z=\frac{x\bar x}{sd}\] \[sd=\frac{x\bar x}{z}\]

yashar806
 2 years ago
Best ResponseYou've already chosen the best response.0why we need to 1 them

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0or rather, we dont have the z value explicitly do we

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1363377005023:dw

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0we have an implicit z, we can either use the zscore of .3/2 .. or 99.7+.3/2

yashar806
 2 years ago
Best ResponseYou've already chosen the best response.0what would be answer?

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0does that make sense? 99.7% is inbetween those values, so the proper zscore has to be adjusted. use z(.9985), at x=196 or, z(.0015), at x=124

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0id prolly use the 196 version

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0can you tell me the zscore of .9985?

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0i agree soo, sd= (196160)/2.96

yashar806
 2 years ago
Best ResponseYou've already chosen the best response.0can we use both of them?

yashar806
 2 years ago
Best ResponseYou've already chosen the best response.0z1 = (124160)/sigma z2 = (196160)/sigma

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0we can, the sd will be negative for the z1 equation and the percentage at z1 is (.0015), iinstead of (.9985)

yashar806
 2 years ago
Best ResponseYou've already chosen the best response.0thats wht i used initially

yashar806
 2 years ago
Best ResponseYou've already chosen the best response.0but i got wrong answer

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0one chk would be to do (124160)/12.1622 and see if its about .0015 :)

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0hmm, i get 2.96 is 160 by chance the average of 124 and 196?
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