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 one year ago
Weights of apples grown in an orchard are known to follow a normal distribution with mean 160 grams. It is known that approximately 99.7% of apples have weights between124 and 196 grams. What is the standard deviation of weights of all apples grown in the orchard?
 one year ago
Weights of apples grown in an orchard are known to follow a normal distribution with mean 160 grams. It is known that approximately 99.7% of apples have weights between124 and 196 grams. What is the standard deviation of weights of all apples grown in the orchard?

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yashar806
 one year ago
Best ResponseYou've already chosen the best response.0but i cant get the right answer

yashar806
 one year ago
Best ResponseYou've already chosen the best response.0i used that that formula

tomo
 one year ago
Best ResponseYou've already chosen the best response.0z1 = (124160)/sigma z2 = (196160)/sigma 1z1z2 = (99.7)/100

tomo
 one year ago
Best ResponseYou've already chosen the best response.0i have to leave, but I think that should help you find the answer

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0dont we just need one of those to determine sigma?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0\[z=\frac{x\bar x}{sd}\] \[sd=\frac{x\bar x}{z}\]

yashar806
 one year ago
Best ResponseYou've already chosen the best response.0why we need to 1 them

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0or rather, we dont have the z value explicitly do we

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0dw:1363377005023:dw

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0we have an implicit z, we can either use the zscore of .3/2 .. or 99.7+.3/2

yashar806
 one year ago
Best ResponseYou've already chosen the best response.0what would be answer?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0does that make sense? 99.7% is inbetween those values, so the proper zscore has to be adjusted. use z(.9985), at x=196 or, z(.0015), at x=124

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0id prolly use the 196 version

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0can you tell me the zscore of .9985?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0i agree soo, sd= (196160)/2.96

yashar806
 one year ago
Best ResponseYou've already chosen the best response.0can we use both of them?

yashar806
 one year ago
Best ResponseYou've already chosen the best response.0z1 = (124160)/sigma z2 = (196160)/sigma

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0we can, the sd will be negative for the z1 equation and the percentage at z1 is (.0015), iinstead of (.9985)

yashar806
 one year ago
Best ResponseYou've already chosen the best response.0thats wht i used initially

yashar806
 one year ago
Best ResponseYou've already chosen the best response.0but i got wrong answer

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0one chk would be to do (124160)/12.1622 and see if its about .0015 :)

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0hmm, i get 2.96 is 160 by chance the average of 124 and 196?
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