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 one year ago
Evaluate the definite integral using the Fundamental Theorem of Calculus.
You will need accuracy to at least 4 decimal places for your numerical answer to be accepted. You can also leave your answer as an algebraic expression involving square roots.
 one year ago
Evaluate the definite integral using the Fundamental Theorem of Calculus. You will need accuracy to at least 4 decimal places for your numerical answer to be accepted. You can also leave your answer as an algebraic expression involving square roots.

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heradog
 one year ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{1}^{3}(\frac{ d }{ dt }\sqrt{5+3t^4})dt\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Hmm so this is a little different than the last one. I think we have something like this going on.\[\large \int\limits_1^3 \frac{d}{dt}f(t)dt \qquad = \qquad \int\limits_1^3 f'(t)dt \qquad = \qquad f(t)_1^3\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1\[\large = f(3)f(1)\] Make sense? :o

heradog
 one year ago
Best ResponseYou've already chosen the best response.0yeah, you just took out the equation itself to understand the format

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Yah these problems are always a little weird. We're differentiating, then antidifferentiating. So we end up with what we started with. Then we just evaluate it at the limits.

heradog
 one year ago
Best ResponseYou've already chosen the best response.0then just go back and put the values into the function getting \[\sqrt{248}\sqrt{8}\] which is right Thanks, thats what I struggle with is where they want me to go with them
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