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anonymous
 3 years ago
Evaluate the definite integral using the Fundamental Theorem of Calculus.
You will need accuracy to at least 4 decimal places for your numerical answer to be accepted. You can also leave your answer as an algebraic expression involving square roots.
anonymous
 3 years ago
Evaluate the definite integral using the Fundamental Theorem of Calculus. You will need accuracy to at least 4 decimal places for your numerical answer to be accepted. You can also leave your answer as an algebraic expression involving square roots.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{1}^{3}(\frac{ d }{ dt }\sqrt{5+3t^4})dt\]

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1Hmm so this is a little different than the last one. I think we have something like this going on.\[\large \int\limits_1^3 \frac{d}{dt}f(t)dt \qquad = \qquad \int\limits_1^3 f'(t)dt \qquad = \qquad f(t)_1^3\]

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1\[\large = f(3)f(1)\] Make sense? :o

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yeah, you just took out the equation itself to understand the format

zepdrix
 3 years ago
Best ResponseYou've already chosen the best response.1Yah these problems are always a little weird. We're differentiating, then antidifferentiating. So we end up with what we started with. Then we just evaluate it at the limits.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0then just go back and put the values into the function getting \[\sqrt{248}\sqrt{8}\] which is right Thanks, thats what I struggle with is where they want me to go with them
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