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heradog
Group Title
Evaluate the definite integral using the Fundamental Theorem of Calculus.
You will need accuracy to at least 4 decimal places for your numerical answer to be accepted. You can also leave your answer as an algebraic expression involving square roots.
 one year ago
 one year ago
heradog Group Title
Evaluate the definite integral using the Fundamental Theorem of Calculus. You will need accuracy to at least 4 decimal places for your numerical answer to be accepted. You can also leave your answer as an algebraic expression involving square roots.
 one year ago
 one year ago

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heradog Group TitleBest ResponseYou've already chosen the best response.0
\[\int\limits_{1}^{3}(\frac{ d }{ dt }\sqrt{5+3t^4})dt\]
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Hmm so this is a little different than the last one. I think we have something like this going on.\[\large \int\limits_1^3 \frac{d}{dt}f(t)dt \qquad = \qquad \int\limits_1^3 f'(t)dt \qquad = \qquad f(t)_1^3\]
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
\[\large = f(3)f(1)\] Make sense? :o
 one year ago

heradog Group TitleBest ResponseYou've already chosen the best response.0
yeah, you just took out the equation itself to understand the format
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.1
Yah these problems are always a little weird. We're differentiating, then antidifferentiating. So we end up with what we started with. Then we just evaluate it at the limits.
 one year ago

heradog Group TitleBest ResponseYou've already chosen the best response.0
then just go back and put the values into the function getting \[\sqrt{248}\sqrt{8}\] which is right Thanks, thats what I struggle with is where they want me to go with them
 one year ago
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