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pandabodoh
Group Title
$HX\left(\frac{1}{\sqrt(2)}0\rangle+\frac{1}{\sqrt(2)}+\rangle\right)$
 one year ago
 one year ago
pandabodoh Group Title
$HX\left(\frac{1}{\sqrt(2)}0\rangle+\frac{1}{\sqrt(2)}+\rangle\right)$
 one year ago
 one year ago

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Jonask Group TitleBest ResponseYou've already chosen the best response.0
\[\left(\frac{1}{\sqrt(2)}0\rangle+\frac{1}{\sqrt(2)}+\rangle\right)\]
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
put \[ instead of $
 one year ago

pandabodoh Group TitleBest ResponseYou've already chosen the best response.0
\[HX\left(\frac{1}{\sqrt(2)}0\rangle+\frac{1}{\sqrt(2)}+\rangle\right)\]
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
is this quantum mechaanics
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
but you are not allowed to ask anything about your edX midterms online remember?
 one year ago

pandabodoh Group TitleBest ResponseYou've already chosen the best response.0
I did not ask about the exam question
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
okay but i am sry i cant help cos i am also taking the course but confused!!! i left qs cos i cud not mange with two courses just left with electricity
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
how far are you
 one year ago

pandabodoh Group TitleBest ResponseYou've already chosen the best response.0
so far I score 59%
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
oh that very good i want to do it but it will disturb my college midterms so i will just do electricity
 one year ago

pandabodoh Group TitleBest ResponseYou've already chosen the best response.0
I need to clarify some concept so I modify the question.
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
y dont you check your notes or ask Turing Test
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
@TuringTest
 one year ago
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