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What is the sum of 9 over the sum of y and 4 + 6 over the difference of y and 3?
 one year ago
 one year ago
What is the sum of 9 over the sum of y and 4 + 6 over the difference of y and 3?
 one year ago
 one year ago

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JonaskBest ResponseYou've already chosen the best response.0
\[\frac{\frac{9}{y+4}+6}{y3}\]
 one year ago

PedroSoccerBest ResponseYou've already chosen the best response.0
the 9/y+4 is separate from the 6/y+3
 one year ago

JonaskBest ResponseYou've already chosen the best response.0
\[\frac{9}{y+4}+\frac{6}{y3}\]
 one year ago

PedroSoccerBest ResponseYou've already chosen the best response.0
Yes, that's correct
 one year ago

JonaskBest ResponseYou've already chosen the best response.0
so wat shud we do????
 one year ago

Kanwar245Best ResponseYou've already chosen the best response.0
step1; take common denominator
 one year ago

JonaskBest ResponseYou've already chosen the best response.0
\[\frac{a}{b}+\frac{c}{d}=\frac{ad+cb}{bd}\]
 one year ago

PedroSoccerBest ResponseYou've already chosen the best response.0
Oh okay so 9(y+3)+6(y+4)/(y+4)(y+3)
 one year ago

electrokidBest ResponseYou've already chosen the best response.1
\[{9\over {y+4}}+{6\over{y3}}={{9(y3)+6(y+4)}\over{(y+4)(y3)}}\]
 one year ago

PedroSoccerBest ResponseYou've already chosen the best response.0
Okay, then we simplify, correct?
 one year ago

electrokidBest ResponseYou've already chosen the best response.1
\[={3(5y1)}\over{(y+4)(y6)}\]
 one year ago

PedroSoccerBest ResponseYou've already chosen the best response.0
Then you distribute the 3
 one year ago

electrokidBest ResponseYou've already chosen the best response.1
haha.. I actually undistributed it...
 one year ago
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