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 one year ago
What is the sum of 9 over the sum of y and 4 + 6 over the difference of y and 3?
 one year ago
What is the sum of 9 over the sum of y and 4 + 6 over the difference of y and 3?

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Jonask
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{\frac{9}{y+4}+6}{y3}\]

PedroSoccer
 one year ago
Best ResponseYou've already chosen the best response.0the 9/y+4 is separate from the 6/y+3

Jonask
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{9}{y+4}+\frac{6}{y3}\]

PedroSoccer
 one year ago
Best ResponseYou've already chosen the best response.0Yes, that's correct

Jonask
 one year ago
Best ResponseYou've already chosen the best response.0so wat shud we do????

Kanwar245
 one year ago
Best ResponseYou've already chosen the best response.0step1; take common denominator

Jonask
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{a}{b}+\frac{c}{d}=\frac{ad+cb}{bd}\]

PedroSoccer
 one year ago
Best ResponseYou've already chosen the best response.0Oh okay so 9(y+3)+6(y+4)/(y+4)(y+3)

electrokid
 one year ago
Best ResponseYou've already chosen the best response.1\[{9\over {y+4}}+{6\over{y3}}={{9(y3)+6(y+4)}\over{(y+4)(y3)}}\]

PedroSoccer
 one year ago
Best ResponseYou've already chosen the best response.0Okay, then we simplify, correct?

electrokid
 one year ago
Best ResponseYou've already chosen the best response.1\[={3(5y1)}\over{(y+4)(y6)}\]

PedroSoccer
 one year ago
Best ResponseYou've already chosen the best response.0Then you distribute the 3

electrokid
 one year ago
Best ResponseYou've already chosen the best response.1haha.. I actually undistributed it...
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