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eiya
Group Title
evaluate lim (x>0) S(x)/(X^3) if S(x)= int (from 0 to x) sin (0.5*pi*t^2)
 one year ago
 one year ago
eiya Group Title
evaluate lim (x>0) S(x)/(X^3) if S(x)= int (from 0 to x) sin (0.5*pi*t^2)
 one year ago
 one year ago

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Koikkara Group TitleBest ResponseYou've already chosen the best response.1
well, it will be helpful, if u could tell us which grade r u in..?
 one year ago

Koikkara Group TitleBest ResponseYou've already chosen the best response.1
Fourier series?
 one year ago

eiya Group TitleBest ResponseYou've already chosen the best response.0
no...only applying indeterminate forms and L'hospital's Rule chapter
 one year ago

Koikkara Group TitleBest ResponseYou've already chosen the best response.1
well, may take some time...dw:1363454097397:dw
 one year ago

eiya Group TitleBest ResponseYou've already chosen the best response.0
i can see yr hardness to write it....appreciate a lot..!
 one year ago

Koikkara Group TitleBest ResponseYou've already chosen the best response.1
@Preetha ....posiibility is like she <<can help you.....
 one year ago

Preetha Group TitleBest ResponseYou've already chosen the best response.0
Nah. I dont have a clue! Try @klimenkov
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
how is t related to x ?
 one year ago

eiya Group TitleBest ResponseYou've already chosen the best response.0
actually there "dt" after the close bracket
 one year ago

AravindG Group TitleBest ResponseYou've already chosen the best response.0
thats better :)
 one year ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.2
\[\lim\limits _{x\rightarrow0}\frac{\int\limits _0^x\sin\frac{\pi t^2}2 dt}{x^3}\] When \(x\rightarrow0\), \(\int\limits _0^x\sin\frac{\pi t^2}2 dt\sim\frac{\pi x^3}{6}\), because \(\sin\frac{\pi t^2}2\sim\frac{\pi t^2}{2}\), when \(t\rightarrow0\). So the limit is \(\frac{\pi}{6}\).
 one year ago

eiya Group TitleBest ResponseYou've already chosen the best response.0
are you applying fundamental theorem?
 one year ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.2
Lol. I have just read what you wrote above about L'hopital's rule. \(\left(\int\limits _0^x\sin\frac{\pi t^2}2 dt\right)'_x=\sin\frac{\pi x^2}2\) \(\left(\sin\frac{\pi x^2}2\right)'_x=\pi x\cos\frac{\pi x^2}2\) So we have \(\lim\limits _{x\rightarrow0}\frac{\int\limits _0^x\sin\frac{\pi t^2}2 dt}{x^3}=\lim\limits _{x\rightarrow0}\frac{\sin\frac{\pi x^2}2}{3x^2}=\lim\limits _{x\rightarrow0}\frac{\pi x\cos\frac{\pi x^2}2}{6x}=\lim\limits _{x\rightarrow0}\frac{\pi \cos\frac{\pi x^2}2}{6}=\frac \pi 6\), because \(\lim\limits_{x\rightarrow0}\cos\frac{\pi x^2}2=1\).
 one year ago

eiya Group TitleBest ResponseYou've already chosen the best response.0
thanks a lot....but im trying to understand the steps..
 one year ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.2
Do you know the L'hopital's rule?
 one year ago

eiya Group TitleBest ResponseYou've already chosen the best response.0
a bit...just learnt last month
 one year ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.2
Do you know what is the derivative?
 one year ago

eiya Group TitleBest ResponseYou've already chosen the best response.0
nahh...i got it...understand already....
 one year ago

eiya Group TitleBest ResponseYou've already chosen the best response.0
yes...i know derivative...
 one year ago

klimenkov Group TitleBest ResponseYou've already chosen the best response.2
You are welcome.
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.0
Welcome to OpenStudy @eiya
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.0
http://prezi.com/fs3hqdpcopic/anunofficialguidetoopenstudy/ ^ A guide for you to start your journey well in openstudy @eiya
 one year ago
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