A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Open

Koikkara
 one year ago
Best ResponseYou've already chosen the best response.1well, it will be helpful, if u could tell us which grade r u in..?

eiya
 one year ago
Best ResponseYou've already chosen the best response.0no...only applying indeterminate forms and L'hospital's Rule chapter

Koikkara
 one year ago
Best ResponseYou've already chosen the best response.1well, may take some time...dw:1363454097397:dw

eiya
 one year ago
Best ResponseYou've already chosen the best response.0i can see yr hardness to write it....appreciate a lot..!

Koikkara
 one year ago
Best ResponseYou've already chosen the best response.1@Preetha ....posiibility is like she <<can help you.....

Preetha
 one year ago
Best ResponseYou've already chosen the best response.0Nah. I dont have a clue! Try @klimenkov

AravindG
 one year ago
Best ResponseYou've already chosen the best response.0how is t related to x ?

eiya
 one year ago
Best ResponseYou've already chosen the best response.0actually there "dt" after the close bracket

klimenkov
 one year ago
Best ResponseYou've already chosen the best response.2\[\lim\limits _{x\rightarrow0}\frac{\int\limits _0^x\sin\frac{\pi t^2}2 dt}{x^3}\] When \(x\rightarrow0\), \(\int\limits _0^x\sin\frac{\pi t^2}2 dt\sim\frac{\pi x^3}{6}\), because \(\sin\frac{\pi t^2}2\sim\frac{\pi t^2}{2}\), when \(t\rightarrow0\). So the limit is \(\frac{\pi}{6}\).

eiya
 one year ago
Best ResponseYou've already chosen the best response.0are you applying fundamental theorem?

klimenkov
 one year ago
Best ResponseYou've already chosen the best response.2Lol. I have just read what you wrote above about L'hopital's rule. \(\left(\int\limits _0^x\sin\frac{\pi t^2}2 dt\right)'_x=\sin\frac{\pi x^2}2\) \(\left(\sin\frac{\pi x^2}2\right)'_x=\pi x\cos\frac{\pi x^2}2\) So we have \(\lim\limits _{x\rightarrow0}\frac{\int\limits _0^x\sin\frac{\pi t^2}2 dt}{x^3}=\lim\limits _{x\rightarrow0}\frac{\sin\frac{\pi x^2}2}{3x^2}=\lim\limits _{x\rightarrow0}\frac{\pi x\cos\frac{\pi x^2}2}{6x}=\lim\limits _{x\rightarrow0}\frac{\pi \cos\frac{\pi x^2}2}{6}=\frac \pi 6\), because \(\lim\limits_{x\rightarrow0}\cos\frac{\pi x^2}2=1\).

eiya
 one year ago
Best ResponseYou've already chosen the best response.0thanks a lot....but im trying to understand the steps..

klimenkov
 one year ago
Best ResponseYou've already chosen the best response.2Do you know the L'hopital's rule?

eiya
 one year ago
Best ResponseYou've already chosen the best response.0a bit...just learnt last month

klimenkov
 one year ago
Best ResponseYou've already chosen the best response.2Do you know what is the derivative?

eiya
 one year ago
Best ResponseYou've already chosen the best response.0nahh...i got it...understand already....

eiya
 one year ago
Best ResponseYou've already chosen the best response.0yes...i know derivative...

mathslover
 one year ago
Best ResponseYou've already chosen the best response.0Welcome to OpenStudy @eiya

mathslover
 one year ago
Best ResponseYou've already chosen the best response.0http://prezi.com/fs3hqdpcopic/anunofficialguidetoopenstudy/ ^ A guide for you to start your journey well in openstudy @eiya
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.